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BigorU [14]
3 years ago
8

How does the height to which each ball bounces back relate to the law of conservation of energy?

Chemistry
1 answer:
olga_2 [115]3 years ago
3 0
<span>If a ball hits the floor after an acceleration then why does it bounces lower? I mean the Energy is passed to the floor then why does the floor give back less Energy?
</span>
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Does anyone have the answers to this worksheet?
abruzzese [7]
Use your periodic table
8 0
3 years ago
Read 2 more answers
HELP ASAP PLEASE!!!
WARRIOR [948]

HCl + NaOH -> NaCl + H2O

reactants: hydrochloric acid HCl

sodium hydroxide NaOh

products: sodium chloride (table salt) NaCl

dihydrogen monoxide (water)

H2O

7 0
3 years ago
Phosphorus-32 has a half-life of 14.3 days. how many grams of phosphorus-32 remain after 71.5 days if you start with 4.00 grams?
almond37 [142]
Answer : 0.125 g

Explanation : If you are calculating the half life of P-32 which has half life of 14.3 days and you want to calculate how many grams are remaining after 71.3 days if yo are starting with 4 g?

starting you can calculate the number of half life P-32 undergoes first,

which is  n = 71.5 / 14.3 = 5 days.

now, to calculate the remaining mass,

m_{remaining}  = (\frac{initial mass}{2 X 2X 2X2 X2 } ) = (\frac{initial mass}{ 2^{5} } )

= = \frac{4 g }{ 2^{5} } = 0.125 g
7 0
3 years ago
How is the polarity of a bond different from the polarity of a molecule?
Andreyy89

Answer:

A polar bond is one where the charge distribution between the two atoms in the bond is unequal. A polar molecule is one where the charge distribution around the molecule is not symmetric. It results from having polar bonds and also a molecular structure where the bond polarities do not cancel.

Explanation:

8 0
3 years ago
Identify the intermediate in the halogenation of alkanes.a) Anionb) Cationc) Radicald) Dimer
Alex_Xolod [135]

Answer: Option C - Radical

Explanation:

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The step by step halogenation process is as follows:

CH4 + Cl2 --> CH3• + HCl + Cl•

CH3• + Cl2 --> CH3Cl + HCl

CH3Cl + Cl2 --> CH2Cl2 + HCl + Cl•

CH2Cl2 + Cl2 --> CHCl3 + HCl

CHCl3 + Cl2 --> CCl4 + HCl + Cl•

Chlorine molecule attack methane knocking off an hydrogen atom from it and forming a methyl radical (CH3•), that is subsequently attack by another chlorine molecule. This cycle repeats itself, until no hydrogen atom is available for substitution by the highly reactive chlorine radical.

Note: no cation or anion is formed in the halogenation process

3 0
3 years ago
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