Where are atoms located? (check all that apply)*

Chemistry

1 answer:

Jobisdone [24]3 years ago

4 0

I think it’s 2 hope that helped

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What is the percent yield if 107.50 g NH3 reacts with excess O2 according to the

Maksim231197 [3]

Answer:

81.59%

Explanation:

4NH₃ + 5O₂ → 4NO + 6H₂O

First we convert 107.50 g of NH₃ into moles, using its molar mass:

107.50 g NH₃ ÷ 17 g/mol = 6.32 mol NH₃

Now we calculate how many moles of NO would have been formed by the complete reaction of 6.32 moles of NH₃:

6.32 mol NH₃ * $\frac{4molNO}{4molNH_3}$ = 6.32 mol NO

Then we convert 6.32 moles of NO to grams, using its molar mass:

6.32 mol NO * 30 g/mol = 189.60 g NO

Finally we calculate the percent yield:

154.70 g / 189.60 g * 100% = 81.59%

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3 years ago

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GarryVolchara [31]

Student B because it requires a hypothesis

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A balloon is filled with 100.0 Lair at 1.300 atm pressure. what pressure is needed to change the volume to 25.00 L

valentinak56 [21]

Answer:

4 atmospheric pressure is needed to get a volume of 25 litres

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3 years ago

What is the total number of oxygen atoms represented in the formula na2c03.10h2o?

Wewaii [24]

As per the given chemical formula- Na2CO3.10H2O, one mole of the chemical compound contains 13 moles of oxygen atoms. Hence

Number of moles of oxygen atoms in one mole of Na2CO3.10H2O = 13

number of moles of oxygen atoms in 0.2 moles of Na2CO3.10H2O = 13 X 0.2 = 2.6

Now, one mole of a substance contains 6.022 X 10^23 particles of the substance. Thus

number of atoms of oxygen in one mole of oxygen atom = 6.022 X 10^23

number of moles of oxygen atoms in 2.6 moles of oxygen atoms = 2.6 X 6.022 X 10^23 = 15.657 X 10^23

= 1.566 X 10^24

Thus, there are 1.566 X 10^24 atoms of oxygen in 0.2 moles of Na2CO3.10H2O.
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3 years ago

What is 20 times 200000000

iren [92.7K]

Answer: 4000000000

because 20X200000000=4000000000

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