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irakobra [83]
3 years ago
8

Can someone match the following ????

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
4 0
I believe it the answer is 3412
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Which of the following is the major product in the electrophilic addition of HCl to (3S)-2,3-dimethylpent-1-ene?
kvv77 [185]

Answer:

(3S)-2-chloro-2,3-dimethylpentane is produced exclusively.

Explanation:

Electrophilic addition to (3S)-2,3-dimethylpent-1-ene proceeds through a carbocationic intermediate.

In the first step, H^{+} adds onto double bond to produce more stable tertiary carbocation. (protonation)

In the second step, Cl^{-} adds onto carbocation to produce (3S)-2-chloro-2,3-dimethylpentane exclusively.(nucleophilic addition)

So, option (d) is correct.

5 0
4 years ago
7. How many electrons can a single orbital hold?
Nat2105 [25]
“It can hold two electrons”
8 0
3 years ago
Read 2 more answers
Geologists have a rule of thumb: when molten rock cools and solidifies, crystals of compounds with the smallest lattice energies
lutik1710 [3]

Geologists have a rule of thumb: when molten rock cools and solidifies, crystals of compounds with the smallest lattice energies appear at the bottom of the mass because of high power of solubility.

<h3>What is lattice energy? </h3>

The lattice energy is defined as the energy change upon the formation of one mole of crystalline ionic compound from its same constituent ions, that are assumed to be initially in the state of gases. It is also defined as measure of the cohesive forces which bind ionic solids together.

As the lattice energy of the ionic compound increase the solubility of that particular compound decrease. Hence compound which have low lattice energy are more soluble than compound having high lattice energy. When molten rocks cools and solidified, the compound having smallest lattice energy become more soluble than crystals of compound which have large lattice energy. Therefore, crystal of compound with the smallest lattice energy start appearing at the bottom of the mass.

Thus, we concluded that due to high solubility power of compound with low lattice energy appear at the bottom of the mass.

learn more about lattice energy:

brainly.com/question/13169815

#SPJ4

4 0
2 years ago
A 96.0 ml volume of 0.25 m hbr is titrated with 0.50 m koh. calculate the ph after addition of 48.0 ml of koh at 25 ∘c.
PilotLPTM [1.2K]
KOH is a strong base and HBr is a strong acid and completely dissociates.
The balanced equation for the reaction is;
KOH + HBr ---> KBr + H₂O
Stoichiometry of acid to base is 1:1
The number of KOH moles reacted - 0.50 M / 1000 mL/L x 48.0 mL = 0.024 mol
number of HBr moles reacted - 0.25 M/ 1000 mL/L x 96.0 mL  = 0.024 mol
the number of H⁺ ions are equal to number of OH⁻ ions. 
Then the solution is neutral.
pH of neutral solutions at 25 °C is 7. 
Therefore pH is 7
8 0
3 years ago
2 KCIO3 - 2 KCl + 302;<br>Type of Reaction?<br><br>​
Ierofanga [76]

Answer:decomposition reaction

Explanation:it is a decomposition reaction

6 0
3 years ago
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