Every sky object sets in the west.
Answer:
The speed of the boat is equal to 13.50 ft/s.
Explanation:
given,
1 nautical mile = 6076 ft
1 knot = 1 nautical mile /hour
1 knot = 6076 ft/hr
speed of boat = 8 knots
8 knots = 8 nautical mile /hour
=
= 13.50 ft/s
The speed of the boat is equal to 13.50 ft/s.
The minimum average speed it must have in the second half of the event in order to qualify is 414.7 km/h.
<h3>
What is average speed?</h3>
The average speed of an object is the ratio of total distance traveled by the object to the total time of motion of the object.
<h3>Total time taken by the car during the entire race</h3>
time = distance/average speed
time = (1.41 km) / (278 km/h)
time = 0.0051 hr
The car travels the first half of the race, d (¹/₂ x 1410 m) at 210 km/h;
d = 705 m = 0.705 km
t1 = 0.705/210
t1 = 0.0034 hr
<h3>time for the second half</h3>
t2 = 0.0051 - 0.0034 hr
t2 = 0.0017 hr
<h3>minimum average speed of the second half</h3>
v = d/t
v = 0.705 km / 0.0017 hr
v = 414.7 km/hr
Thus, the minimum average speed it must have in the second half of the event in order to qualify is 414.7 km/h.
Learn more about average speed here: brainly.com/question/4931057
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Answer: depth= 1875m
Explanation: divide t by 2 because its echo it will go and come back thats why we divide it with 2
Then apply formula Depth(d)=velocity (v)/time (t)
Putting values we get ,
d=1500/0.4
d=1875m
Gravitational force = G · m₁ · m₂ / r²
' G ' is the 'universal gravitational constant, 6.673 x 10⁻¹¹ m³/kg-s²
m₁ = 60 kg
m₂ = 120 kg
r = 5 m
F = (6.673 x 10⁻¹¹ m³/kg-sec²) · (60 kg) · (120 kg) / (5m)²
F = (6.673 x 10⁻¹¹ · 60 · 120 / 25) · (m³ · kg · kg / kg · s² · m²)
F = 1.922 x 10⁻⁸ (kg · m / s²)
<em>F = 1.922 x 10⁻⁸ Newton</em> (about 0.0000000692 ounce of force)
