De acordo com a disponibilidade da unidade, há apenas a seguinte dosagem: 1g/2mL - ou seja, uma grama de dipirona a cada 2mL
O enunciado está meio mal formulado, pois é dito que foram prescritos 500mg de dipirona e é essa quantidade de farmaco que a criança tem que tomar. Deseja-se saber quantos mL deverao ser administrados.
Fazendo a classica regra de 3, podemos chegar no volume desejado:
(atentar que 500mg = 0,5g)
g mL
1 --------- 2
0,5 --------- X
1 . X = 0,5 . 2
<h3>X = 1mL</h3>
Answer:
Step-by-step explanation:
To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.
Area of the square.
To calculate the area of the square you have to calculate the square of one of its sides, following the formula:
Where "a" is the length of one of its side.
The side length of the square is a=7cm, so its area will be:
Area of the triangles.
The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.
To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:
The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:
Now that the area of all shape are calculated, you have to add them to determine the area of the logo:
Answer: The angles of ΔA'B'C are congruent to the corresponding parts of the original triangle.
Step-by-step explanation:
Given : Triangle ABC was rotated 90 degrees clockwise. Then it underwent a dilation centered at the origin with a scale factor of 4.
A rotation is a rigid transformation that creates congruent images but dilation is not a rigid transformation, it creates similar images but not congruent.
Also, the corresponding angles of similar triangles are congruent.
Therefore, The angles of ΔA'B'C are congruent to the corresponding parts of the original triangle.
I need to answer two questions to ask again sorry