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Amanda [17]
4 years ago
8

A 7.2 m long ramp is set at an angle of 42 degrees with the floor. An 11kg box is pushed up the ramp. What is the change in GPE

of the box? (Answer is 340J, but how do you get that?)
Physics
1 answer:
Evgesh-ka [11]4 years ago
7 0

Answer:

Answer is 519.3 J

Explanation:

GPE = m x g x h

Object Height is equal to 7.2 x sin42  = 7.2 x 0.669 = 4.817m

GPE = 11 x 9.8 x 4.817 =519.3 J

Most probably m value (11kg) has been used as 7.2 mistakenly.

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I NEED HELP ASAPPPP!!
Juli2301 [7.4K]

Increase in wavelength will cause decrease in frequency. When wavelength doubles, the frequency of the wave will reduce to half of its value.

<h3>WAVE SPEED</h3>

The wave speed is the product of wave frequency and its wavelength.

v = f⋅λ

  • v = the speed of a wave
  • f = frequency
  • λ = wavelength

For example, if a wave has a frequency of 120 Hz and a wavelength of 5m, it would have a speed of 600 m/s.

if the wavelength is increased to 10m but the speed stays the same at 600 m/s. That is,

λ = 10m

v = 600 m/s

v = f⋅λ

Substitute f and v into the formula

600 = 10f

f = 600 / 10

f = 60 m

The frequency of the wave is reduced to half of its value.

Learn more about wave speed here: brainly.com/question/2847127

8 0
2 years ago
Pls help i begg youuuuu
Anna [14]
Pitch is the sensation of certain frequencies to the ear. High frequency = high pitch, low frequency = low pitch. 

f = c(speed of the wave) /  <span>λ (wavelength)

1. 343m/s / 0.77955m = 439.99 Hz   
     This corresponds to pitch A 

2. 343m/s / 0.52028m = 659.26 Hz
</span>     This corresponds to pitch E 
<span>
3. 343m/s / 0.65552m = 523.349 Hz
    </span>This corresponds to pitch C

4. using f = c /  λ
  λ = c / f<span>
     = 343m/s / 587.33 = 0.583999 m = 0.584 m

</span>
3 0
3 years ago
On your first attempt you leave the surface of the earth at v = 5534 m/s. how far from the center of the earth will you get?
Tamiku [17]
<span>It's another energy balance equation, though: energy to start with is the same as energy that you end with. Suppose that we start a distance r0 from the Earth and end a distance r1 from the Moon, then the energy balance gives: 1 v02 - G M / r0 - G m / (D - r0) = 1 v12 - G M / (D - r1) - G m / r1 ...where m is the moon's mass. One simple limit takes D ? ? and 1 v02 ? G M / r0 (the escape velocity equation), to yield: 1 v12 ? G M / r1 v1 ? ?( 2 G M / r1 ) = 2377 m/s.</span>
8 0
3 years ago
Which statement BEST compares the force of gravity on a school bus on a school day and a weekend? *
inna [77]

Answer:

(A) The force would be lower on the school day than the weekend.

Explanation:

In  a  school  day  the  bus  is  on  the  road  travelling  with  kids.  But  in  a  weekend  it  is  parked.  When  a  object  stays  still  that  means  the the  force  which  is  working  on  the  earth  by  the  bus  is  equal  to  the  force which  works  on  the  bus  by  the  earth. we  can  understand  it  clearly by,  Newton's second law of motion.  

This pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.  so  as  it  is  when  it  is  balanced  it  is  not  moving.

And  on  a  school  day  the  bus  is  moving  so  it  has  a  force  pulling  itself  forward .  so  it  means  that  the  force  which  the  bus  has  is  greater  than  the  gravitational  force.

7 0
3 years ago
Identify each of the cell structures in the figure
nexus9112 [7]
Fair enough ! Where's the figure ?
3 0
3 years ago
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