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scoray [572]
3 years ago
13

Which statement BEST compares the force of gravity on a school bus on a school day and a weekend? *

Physics
1 answer:
inna [77]3 years ago
7 0

Answer:

(A) The force would be lower on the school day than the weekend.

Explanation:

In  a  school  day  the  bus  is  on  the  road  travelling  with  kids.  But  in  a  weekend  it  is  parked.  When  a  object  stays  still  that  means  the the  force  which  is  working  on  the  earth  by  the  bus  is  equal  to  the  force which  works  on  the  bus  by  the  earth. we  can  understand  it  clearly by,  Newton's second law of motion.  

This pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.  so  as  it  is  when  it  is  balanced  it  is  not  moving.

And  on  a  school  day  the  bus  is  moving  so  it  has  a  force  pulling  itself  forward .  so  it  means  that  the  force  which  the  bus  has  is  greater  than  the  gravitational  force.

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Answer:

If the Kelvin temperature of a gas is increased, the volume of the gas increases. This can be understood by imagining the particles of gas in the container moving with a greater energy when the temperature is increased.

Explanation:

If you heat a gas you give the molecules more energy so they move faster. This means more impacts on the walls of the container and an increase in the pressure. Conversely if you cool the molecules down they will slow and the pressure will be decreased.

To calculate a change in pressure or temperature using Gay Lussac's Law.

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Darren filled ocean water, fresh water, bottled water, and tap water into four different containers. He then dropped identical g
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Two 2.0cm×2.0cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 v battery. What is the
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Answer:

The charge on each electrode is

q=0.354 x10^{-12}

Explanation:

The charge to find the equation is development

V=9v

d=1.0 mm\\A=2cm*2cm=0.02m*0.02m\\A=4x10^{-4} \\E_{o} =8.85x10^{-12} (\frac{C^{2} }{N*m^{2} } )

q=C*V

C=\frac{E_{o}*A }{d} \\C=\frac{8.85x10^{-12} *4x10^{-4}  }{0.01}=0.354  \\

q=0.354*9v\\q=3.186x10^{-12} C

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