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astraxan [27]
2 years ago
5

What is the center and radius of the circle defined by the equation (x-4)^2+(y-7)^2=49

Mathematics
2 answers:
alex41 [277]2 years ago
8 0

Answer:

center (4,7)

radius 7

Step-by-step explanation:

The number in the parentheses with the x and with the y tell you the center of the circle is at 4, 7. The other side of the equation is 49, which is r squared. So the radius is 7

Per Khan academy:

The general equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius

AlekseyPX2 years ago
4 0

Answers:

Center = (4, 7)

Radius = 7

===========================================================

Explanation:

The general template of any circle is

(x-h)^2 + (y-k)^2 = r^2

This general circle has these properties:

  • Center = (h,k)
  • Radius = r

Based on the equation your teacher gave you, we see that

  • h = 4
  • k = 7
  • r = 7, since 7^2 = 7*7 = 49

Therefore, this circle has center = (4,7) and radius = 7

Side note: The center's y coordinate and radius aren't always the same value.

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3 years ago
Please need this answer fast it is the last piece to my pie chart for math!!!! A catering service offers 3 appetizers, 5 main co
Brut [27]
To find in how many ways this can be done, we can use the method of combination.

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For 6 out of 8 desserts, the combination would be 8C6.

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7 0
3 years ago
Solve the system of equations using any method. 2X – Y + Z = – 2, 6X + 3Y – 4Z = 8, – 3X + 2Y +3Z = – 6
krok68 [10]

Answer:

Z = - 2, Y = 0, X = 0

Step-by-step explanation:

2X – Y + Z = – 2

6X + 3Y – 4Z = 8

– 3X + 2Y +3Z = – 6

isolate "X" in the first equation

2X - Y + Z = - 2 => isolate "2X"

2X = - 2 - Z + Y => divide either side by 2

X = - 1 - Z/2 + Y/2

substitute this value of X in the second two equations (applying the substitution method here)

6(- 1 - Z/2 + Y/2) + 3Y - 4Z = 8,

6Y - 7Z - 6 = 8

- 3(- 1 - Z/2 + Y/2) + 2Y +3Z = - 6,

Y + 9Z + 6/2 = - 6

isolate Y in the second equation (6Y - 7Z - 6 = 8) and substitute in the third equation (Y + 9Z + 6/2 = - 6)

6Y - 7Z - 6 = 8 => isolate 6Y

6Y = 14 + 7Z => divide either side by 6

Y = 7Z + 14/6 => substitute in second equation

7Z + 14/6 + 9Z + 6/2 = - 6 => solve for Z

61Z + 50/12 = - 6, Z = - 2

substitute the value of Z into the equations "Y = 7Z + 14/6" and using the value of Y and Z, substitute into "X = - 1 - Z/2 + Y/2"

Y = (7(- 2) + 14)/6 = 0 / 6

= 0

X = - 1 - (- 2)/2 + 0/2 = - 1 - (-1) + 0

= - 1 + 1 + 0 = 0

6 0
2 years ago
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