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astraxan [27]
2 years ago
5

What is the center and radius of the circle defined by the equation (x-4)^2+(y-7)^2=49

Mathematics
2 answers:
alex41 [277]2 years ago
8 0

Answer:

center (4,7)

radius 7

Step-by-step explanation:

The number in the parentheses with the x and with the y tell you the center of the circle is at 4, 7. The other side of the equation is 49, which is r squared. So the radius is 7

Per Khan academy:

The general equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius

AlekseyPX2 years ago
4 0

Answers:

Center = (4, 7)

Radius = 7

===========================================================

Explanation:

The general template of any circle is

(x-h)^2 + (y-k)^2 = r^2

This general circle has these properties:

  • Center = (h,k)
  • Radius = r

Based on the equation your teacher gave you, we see that

  • h = 4
  • k = 7
  • r = 7, since 7^2 = 7*7 = 49

Therefore, this circle has center = (4,7) and radius = 7

Side note: The center's y coordinate and radius aren't always the same value.

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Answer:

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Step-by-step explanation:

To find f'(x), we will follow the steps below:

We will start by integrating both-side of the equation

∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx

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Then we go ahead and find C

f(1) = 8

so we will replace x by 1 in the above equation and solve for c

f(1)  = 3(1)⁴ - \frac{2(1)^{3} }{3} - 17(1) + C

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C =8 - 3 + 17 + \frac{2}{3}

C = 22 +  \frac{2}{3}

C =\frac{66 + 2}{3}

C = \frac{68}{3}

f(x) =  3x⁴ - \frac{2X^{3} }{3} - 17x +  \frac{68}{3}

7 0
3 years ago
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Answer:

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Step-by-step explanation:

x^2+ 12x + 36 = 0

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x^2+ 12x + 36-36 = 0-36

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Answer:

C. 60%

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