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astraxan [27]
3 years ago
5

What is the center and radius of the circle defined by the equation (x-4)^2+(y-7)^2=49

Mathematics
2 answers:
alex41 [277]3 years ago
8 0

Answer:

center (4,7)

radius 7

Step-by-step explanation:

The number in the parentheses with the x and with the y tell you the center of the circle is at 4, 7. The other side of the equation is 49, which is r squared. So the radius is 7

Per Khan academy:

The general equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius

AlekseyPX3 years ago
4 0

Answers:

Center = (4, 7)

Radius = 7

===========================================================

Explanation:

The general template of any circle is

(x-h)^2 + (y-k)^2 = r^2

This general circle has these properties:

  • Center = (h,k)
  • Radius = r

Based on the equation your teacher gave you, we see that

  • h = 4
  • k = 7
  • r = 7, since 7^2 = 7*7 = 49

Therefore, this circle has center = (4,7) and radius = 7

Side note: The center's y coordinate and radius aren't always the same value.

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