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3 years ago

Is the quotient of two integers always a rational number? Explain.

Mathematics

1 answer:

Troyanec [42]3 years ago

4 0

Answer:

It is true that the quotient of two integers is always a rational number. This is because a rational number is any number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.

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ok so um yea plz help....and if you find them i will do 2 thingss............face reveil anddddddddd BRAINLEIST for you

blagie [28]

Answer:

Step-by-step explanation:

all you have to do is divide 12 by 3

3 0

3 years ago

Read 2 more answers

What is the result of substituting for y in the bottom equation y=x+3 y=x^2+2x-4

8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

Solution:

Given that,

$y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4 ----- eqn 2$

We have to substitute eqn 1 in eqn 2

$x + 3 = x^2 + 2x - 4$

$\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0$

$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$

$x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}$

$x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925$

$Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925$

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0

3 years ago

If 66 oranges cost $15, how many oranges can be purchased for $5?

Rasek [7]

Answer:

22 oranges

Step-by-step explanation:

$15 --- 66 oranges

$5 --- $\frac{5}{15}$ × 66 oranges = 22 oranges

7 0

3 years ago

Math:(

dimulka [17.4K]

Answer:

Your friend is incorrect because if you divide 21 by 7 you will get 3 if you add 7 to 3 you get 10 therefore your friend is incorrect.

6 0

3 years ago

Show 46/200 on the hundredths grid. then write the fractions as a demical

SSSSS [86.1K]

If we want to has 100 in the denominator we have to divide numerator and denominator by 2. Then total value of fraction doesnt change.
$\frac{46}{200}= \frac{46:2}{200:2}= \frac{23}{100}$
Now read the fraction, its 23 hundreds, now just write as decimal, so, 0.23

3 0

3 years ago