Answer:
The column of methanol is = 12.27 m high
Explanation:
The pressure of mercury (p) = ghd,................... equation 1
Where g = acceleration due to gravity, h= height, d = density.
d = 13.6 g/ml convert to kg/m³ = 13.6 g/ml(1000 (kg/m³)/(g/ml))
d =13600 kg/m³., h= 713mm = 713/1000 = 0.713 m., g= 9.80 m/s²
Substituting these values into equation 1,
P = 13600 × 0.713 × 9.8 = 95028.64 N/m².
If the pressure of the mercury supports the pressure exerted by the methanol
∴ pressure that supports the mercury = pressure of the methanol
p = ghd
making h the subject of formula,
h = p/gd ........................... equation 2
Where p = 95028.64 N/m², g = 9.8 m/s², d = 0.79 g/ml = (0.79 × 1000) kg/m³
d = 790 kg/m³.
Substituting these values into equation 2
h = 95028.64/(9.8×790)
h = 95028.64/7742
h = 12.27 m.
The column of methanol is = 12.27 m high
