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kirza4 [7]
2 years ago
5

A 3.2-gram sample of air contains 0.000 74 gram of hydrogen cyanide. Determine the concentration, in parts per million, of the h

ydrogen cyanide in this sample.
Chemistry
1 answer:
notka56 [123]2 years ago
7 0
 The answer is: 231.25 ppm. 
To solve this, compute first the percentage of hydrogen in the 3.2 g air sample. % = (0.00074g/3.2g)*100 = 0.023125%
1% = 10,000ppm <--- use this as conversion factor. 

0.023125%(10,000ppm/1%) = 231.25 ppm 
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The pOH of a solution is 10.75. What is the concentration of OH– ions in the solution?. A. –1.031 M. B. 1.778 x 10–11 M. C. 5.62
zloy xaker [14]
We are given the pOH of the solution of 10.75. pOH is the property of the solution that is related to the OH ion concentration of the solution. THe formula to be followed is pOH = -log (OH); OH- = 10^-pOH. In this case, OH-  = 10^-10.75 equal to B. 1.778 x 10^-11 M
5 0
3 years ago
Help please i am very dumb
UkoKoshka [18]

Answer:

1. 25%

2. 1.25

3. 1

Explanation:

Be sure to look at the x and y axis to answer these questions. All you need to do is look at the graph.

- Hope that helps! Please let me know if you need further explanation.

7 0
3 years ago
Calcium bicarbonate (Ca(HCO3)2) Ca:H:C:O = 1:2:2 ___ Lithium sulfide (Li:2s) Li:S = 2:__
Anastaziya [24]

Answer: The ratio of atoms in calcium bicarbonate ; Ca : H : C : O = 1:2:2:6.

The ratio of atoms in lithium sulfide; Li : S = 2 : 1

Explanation:

In calcium bicarbonate:Ca(HCO_3)_2

In a molecular formula of calcium carbonate there are:

Number of Calcium atoms = 1

Number of Hydrogen atom = 1 × 2 = 2

Number of Carbon atoms = 1 × 2 = 2

Number of Oxygen atoms = 3 × 2 = 6

So, Ca : H : C : O = 1 : 2 : 2 : 6

In lithium sulfide :Li_2S

In a molecular formula of lithium sulfide there are:

Number of Lithium atoms =  1 × 2 = 2

Number of Sulfur atoms = 1

So, the Li : S = 2 : 1

8 0
3 years ago
A ______ solution contains more dissolved solute than a saturated solution at the same temperature
NeTakaya

Answer:

i believe the answer is supersaturated  

Explanation:

5 0
3 years ago
Part d based on your answer to part c, how many bonding electrons and lone pair electrons (nonbonding electrons) are there in th
elena55 [62]
The Lewis Structure of HCN is shown below,

Number of Bonding Electrons:
                                               In HCN Hydrogen is bonded to Carbon through single bond and Nitrogen is bonded to Carbon through Triple Bond. Single bond is formed by two bonding electrons, while, triple bond is formed by six bonding electrons, Hence,

                               Number of Bonding Electrons  =  8

Number of Non-Bonding Electrons:
                                                            In HCN there is only one lone pair of electron present on Nitrogen atom which is not taking part in bonding. Hence, 
                              Number of Non-Bonding Electrons  =  2

Result:

                               Number of Bonding Electrons  =  8

                              Number of Non-Bonding Electrons  =  2

3 0
3 years ago
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