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algol13
3 years ago
5

?cual es el tiempo deonda con 6oscilaciones.?​

Chemistry
1 answer:
Setler79 [48]3 years ago
7 0

Answer:

Hey hi

Explanation:

Can you pls tell me which language is this.... Pls really sorry... I wanna help you

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Why is it not a good idea to use a stopper when combining two unknown substances in  test?
Colt1911 [192]
Hi!

You would not want to use a stopper when<span> combining two unknown substances because the gasses made from the combination could end up creating to much pressure and explode.</span>
6 0
4 years ago
Which characteristics help enable plants to survive on earth ?
Liula [17]
Plants use carbon dioxide, and put out oxygen, so it's like a cycle there. plants have roots to collect water from the soil around them. And they use the sun for energy.
4 0
3 years ago
Which ligand binds tightest? ligand A, with a dissociation constant ( Kd ) of 10−9 M ligand D, with a percent occupancy of 80% a
Delvig [45]

Answer:

The answer will be Ligand A with a dissociation constant (Kd) of 10^{-9}M

Explanation:

When the dissociation constant in the ligand is small (in order of nano) ( 10^{-9}) it will be more tied. Due to a dissociation constant measures how much a ligand can be able to be separated from the protein so if the number is small it means that the ligand is highly binded to the protein.

On the other hand, the occupancy percentage of the ligand does not imply binding. Conversely, a High-affinity ligand binding with the proteins implies that a relatively low concentration of a ligand is adequate to occupy the maximum ligand-binding site.

6 0
3 years ago
Mass=1.01 kg; volume =1000cm3
guajiro [1.7K]

Density = 1.01 g/cm^3 or 1.01 kg/dm^3 or 1010 kg/m^3

Density = mass/volume = 1010 g/1000 cm^3 = 1.01 g/cm^3 = 1.01 kg/dm^3

= 1010 kg/m^3


7 0
3 years ago
A substance has a solubility of 350 ppm.how many grams of the substance are present in 1.0l of a saturated solution
sergeinik [125]
Since the given solubility is 350 ppm, convert it first with fraction of solubility. by dividing the solubility with 10^6
S = 350 / 10^6
s = 3.5 x 10^-4
the multiply it to the total solution to calculate the amount of substance present
m = ( 3.5 x 10^-4 ) ( 1.01 )
m = 3.535 x 10^-4 g of the substance present
6 0
3 years ago
Read 2 more answers
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