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algol13
3 years ago
5

?cual es el tiempo deonda con 6oscilaciones.?​

Chemistry
1 answer:
Setler79 [48]3 years ago
7 0

Answer:

Hey hi

Explanation:

Can you pls tell me which language is this.... Pls really sorry... I wanna help you

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HELP ME! If I get an F on my test I’m getting kicked out:(
satela [25.4K]

Answer:

It is just slightly less abundant than its alkali cousin, sodium. Potassium is less dense than water, so it can float on water. However, chemically, potassium reacts with water violently. It will give off hydrogen and eventually catch fire.

3 0
3 years ago
Can cells have different types of openings?
Tcecarenko [31]

Answer:

Yes they can.

Explanation:

4 0
3 years ago
A solution of sugar contains 35 gramsof sucrose, C12H22O11in 100 mL of water. What is the percent composition of the solution?
KATRIN_1 [288]

Answer:

Percent composition of the solution is 26 % of sucrose and 74 % of water

Explanation:

Percent composition is the mass of solute, either of solvent in 100 g of solution.

Mass of solution = Mass of solvent + Mass of solute

Mass of solute = 35 g

Mass of solvent = 100 g

As we know, water density = 1g/mL

So 1g/mL . 100 mL = 100 g

35 g + 100 g = 135 g → Mass of solution

(Mass of solute / Mass of solution) . 100 =

(35 g / 135 g) . 100 = 26 %

(Mass of solvent / Mass of solution) . 100 =

(100 g / 135 g) . 100 = 74 %

8 0
3 years ago
A certain weak acid, ha, has a ka value of 6.0×10−7. calculate the percent ionization of ha in a 0.10 m solution.
joja [24]
For the purpose, we will use the equation for determining the dissociation constant from concentration and <span>percent of ionization:

Kd = c </span>× α²

α = √(Kd/c) × 100%

Kd = 6.0×10⁻⁷

c(HA) = 0.1M

α = √(6.0×10⁻⁷/0.1)  × 100% =  0.23%

So, in the solution, the acid <span>percent of ionization will be just 0.23%.</span>

5 0
3 years ago
Neon doesn't take part in chemical reaction why give reason​
ankoles [38]
Neon has filled its outer shells, therefore it is very stable and does not need to react with other elements and doesn’t form compounds.
5 0
3 years ago
Read 2 more answers
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