You cant find a nucleus in bacteria you see under a microscope. why
2 answers:
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Answer:
Given a set of assumptions which are given below, the height at which the pomegranate will have the same potential energy as the melon is 39.19 meters.
Explanation:
Gravitational Potential Energy refers to the acquired innate energy of an object due to its elevation above the surface of the earth.
This energy is the result of gravitational pull or force acting on the object.
In other to determine at what height a pomegranate and a watermelon will have the same potential energy we need to know the other factors in play.
Gravitational Potential Energy (E<em>p</em>)= <em>mgh</em>
Where m = Mass (kg)
g = gravitational field strength (N/kg)
h = height (m)
E<em>p </em>= gravitational potential energy ( <em>j </em>)
Let us assume that the
- An average pomegranate weighs about 0.255146Kg
- An average melon weighs about 10Kg
- g is always constant at 9.8 N/kg
Note that melons weight much more than pomegranates.
So, let's calculate for the E<em>p </em>of the melon at the height of 1 meter
E<em>p</em> = 10 x 9.8 X 1 = 98<em>j</em>
Using the above assumptions, we do a goal seek using Microsoft Excel. Please see the attached image.
Calculation shows that the Height (h/Meters) at which the E<em>p </em>of both veggies become equal is 39.19m
This can be verified by inserting the figure and multiplying it. It can also be calculated as follows:
That is
E<em>p = 98j</em>
<em>m = </em>0.255146kg
<em>g= 9.8kg</em>
<em>h= ?</em>
98= 0.255146 x 9.8 x <em>h</em>
98 = 2.5004308<em>h (we divide both sides by </em>2.5004308 to make h the subject matter<em>)</em>
<em>h = 98 / </em>2.5004308
<em>h = 39.1932462198</em>
Which is approximately 39.19
Answer:
Frequency of heterozygous animals with agouti fur is %
Explanation:
As per the Hardy Weinberg's equation -
represents the frequency of population with phenotype expressed by homozygous recessive genotype
represents the frequency of population with phenotype expressed by homozygous dominant genotype
and represents the frequency of population with phenotype expressed by homozygous recessive genotype
Given -
As per first principle of Hardy Weinberg's equilibrium
Substituting the value of q in above equation, we get -
As per second principle of Hardy Weinberg's equilibrium
Substituting the given values in above equation, we get -
Frequency of heterozygous animals with agouti fur is %