What is the mole fraction of NaBr in

The radioactive atom R 88 210 a is an alpha emitter. What nucleus does it produce?

olasank [31]

Answer:

X 86 206

Explanation:

Radioactive atoms are nuclei that can under go disintegration to emit either an alpha particle, beta particle or gamma radiation. The process could be spontaneous or stimulated.

When a radioactive atom R 88 210 emits alpha particle, it would produce an element with atomic number 86 and mass number 206 i.e X 86 206. An alpha particle is usually a helium nucleus.

$R^{210}$ ⇒ $x^{206}$ + $He^{4}$ + energy

5 0

3 years ago

The least active elements are the _______.

Andreas93 [3]

Noble gases are the least reactive elements in the periodic table because they have a full valence shell. Examples are, Argon, Neon, Xenon, and Helium

4 0

2 years ago

Before you start an investigation, you see the Hazard symbol for Electrical Hazard. What safety steps should you follow when con

Fantom [35]

Explanation:

Safety hazards means they are are the unsafe working conditions which can cause the workmen injury, illness, or death. Safety hazards are some of the most common risks at the workplace.

Electrical hazards may be defined as a place or a condition which is dangerous and where a person working can come in contact with electrical contact with some energized equipment or any electrical conductor. There is always danger or a chance for the workmen to get injury or get a flash burn while working.

The safety steps are :

1. Follow the instruction properly

2. Take proper safety measures like wearing gloves, shoes, not touching any live wires, etc.

3. Follow the clean up procedure properly.

7 0

2 years ago

The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p

zysi [14]

Answer : q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

$q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})$ (in terms of mass)

or, $q=\Delta H_{fusion}\times Moles$ (in terms of moles)

Now we have to calculate the value of q.

$q=6020J/mole\times 1Mole=6020J$

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of $\Delta e=0$

Now we have to calculate the value of w.

Formula used : $\Delta e=q+w$

where, q is heat required, w is work done and $\Delta e$ is internal energy.

Now put all the given values in above formula, we get

$0=6020J+w$

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

3 0

3 years ago

A car with a mass of 1,200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. The centri

Helga [31]

The answer is 80 m.

Centripetal force (F) is a force that makes body move around a circular curve. The unit of force is N (N = kg * m/s²).
It can be represented as:
$F= \frac{m* v^{2} }{r}$
where:
m - mass
v - velocity
r - radius of the curve

We have:
m = 1,200 kg
V = 20 m/s
F = 6,000 N = 6,000 kg * m/s²

We need radius of the curve:
r = ?

So, if $F= \frac{m* v^{2} }{r}$ , then:
 $r= \frac{3* v^{2} }{F}$
⇒ $r = \frac{1200 kg * (20m/s)^{2} }{6000 kg*m/s^{2} }$
⇒ $r= \frac{1200*400*kg*m^{2}*s^{2} }{6000kg*m/s^{2} }$
⇒ $r= \frac{480,000m}{6000}$
⇒ $r=80m$

6 0

3 years ago