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4 years ago

5

The chemical formula tells the types of atoms and how many of each are contained in a compound. Please select the best answer fr

om the choices provided
a. True
b. False

1 answer:

kykrilka [37]4 years ago

7 0

The anser should be false

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A piece of limestone erodes due to acid rain. This process can be best described as a......

arsen [322]

Slow chemical change

It is a chemical change because the erosion is due to the chemical reaction between the acid and the in the rain and the calcium carbonate.

It is slow due to the concentration of acid is low.

3 0

3 years ago

(5.0 m3) ( 7.5 mmHg) = (P)(4.0m3)

anzhelika [568]

It looks like we are solving for a pressure. All that is required is some algebraic manipulation to find our pressure in mmHg.

Given:

(5.0 m³)(7.5 mmHg) = (P)(4.0m³)

Multiply:

37.5 = 4.0P

Divide:

9.375 = P

P = 9.4 mmHg (remember sig figs)

<h3>Answer:</h3>

9.4 mmHg

7 0

3 years ago

Give an example, other than making ice-cream or a slushy, where the effect of salt on the phase change of water is useful in eve

guapka [62]

Answer:

Putting salt on the ground to melt ice or snow I mean.

Explanation:

7 0

4 years ago

Read 2 more answers

The solid compound, K2SO4, contains?

givi [52]

The solid compound, K2SO4 contains a cation called K+ and an anion called SO42-. In this case, there are 2 atoms of potassium, 1 atom of sulfur and 4 moles of oxygen. The compound also contains ionic bonds because of the composing non-metals and metal.

3 0

4 years ago

What is the molarity of solution that is 5.50 percentage by mass oxalic acid and has a density of 1.024 g/ml

Y_Kistochka [10]

Answer:

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

Explanation:

Mass percentage of oxalic acid = 5.50%

This means that in 100 grams of solution there are 5.50 grams of oxalic acid.

Mass of solution , m = 100

Volume of the solution = V

Density of the solution = d = 1.024 g/mL

$V=\frac{m}{d}=\frac{100 g}{1.024 g/mL}=97.66mL$

V = 97.66 mL = 0.09766 L

(1 mL = 0.001 L)

Moles of oxalic acid = $\frac{5.50 g}{90 g/mol}=0.06111 mol$

$Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}$

The molarity of the solution :

$=\frac{0.06111 mol}{0.09766 L}=0.6257M$

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

6 0

3 years ago