3 years ago

The image shows water passing through a barrier.

Physics

2 answers:

Aloiza [94]3 years ago

8 0

C is the answer for this question

zloy xaker [14]3 years ago

3 0

It is diffraction

Explanation:

The opening is the aperture

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While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the

BartSMP [9]

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

$d = v_i * t + \frac{1}{2} at^2$

$d = 0 + \frac{1}{2}*9.8* 1.5^2$

$d = 4.9 * 2.25$

$d = 11.025 m$

so the bag will fall down by total distance of 11.025 m from its initial released position.

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3 years ago

Bodies weighing 1 kilogram and 5 kilograms lie on a smooth horizontal surface. If a traction force of 0.6 N acts on another 5 kg

natima [27]

0.6/5,1,5

so calculate it

not so sure though

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3 years ago

A liquid thermometer can be used to test for fevers. When body temperature increases,

aleksandr82 [10.1K]

Answer:A

Explanation:

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3 years ago

What are 2 examples of levers

GaryK [48]

Answer:

Some examples of levers include more than one class, such as a nut cracker, a stapler, nail clippers, ice tongs and tweezers. Other levers, called single class levers include the claw end of a hammer.

Explanation:

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3 years ago

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You want to manufacture a guitar such that the instrument will be in tune when each of the strings are tightened to the same ten

charle [14.2K]

Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

$\mu$ = Mass density of string

E denotes the E string

D denotes the D String

Frequency is given by

$f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}$

$f\propto \sqrt{\dfrac{1}{\mu}}$

$\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m$

The mass density of the E string is 0.000507 kg/m

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3 years ago