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olasank [31]
3 years ago
8

San

Physics
2 answers:
Solnce55 [7]3 years ago
7 0

Answer:

40 W

Explanation:

P = Fd/t

P = (10N )(8m)/2s

P = 80/2

P = 40 W

erica [24]3 years ago
3 0

Answer: 1) 40W

Explanation:

Power formula

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MariettaO [177]

Answer: The theory of Plate Tectonics is now widely accepted because there is sufficient proof to support it, and it is an important aspect of geology, oceanography, geophysics and even paleontology.

Explanation: In places where a plate faced resistance to its movement, it would fold upward and create mountains. Hope this helped! :)

6 0
3 years ago
What is physics and important of physics​
Arte-miy333 [17]

Answer:

Physics is the answer to all the forces in nature and it is important to know all of that in a day to day life to succeed in life

Explanation:

4 0
3 years ago
Read 2 more answers
n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend
Kitty [74]

Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

p_f=p_i\\mv_1+Mv_2=(m+M)v

m: mass of the bullet

M: mass of the pendulum

v1: velocity of the bullet = 410m/s

v2: velocity of the pendulum =0m/s

v: velocity of both bullet ad pendulum joint

By replacing you can find v:

(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2

g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

(0.038kg+4.2kg)(9.8m/s^2)h=\frac{1}{2}(0.038kg+4.2kg)(3.67m/s)^2\\\\h=0.68m

hence, the heigth is 68cm

4 0
3 years ago
Jupiter's semimajor axis is 7.78×1011 m. The mass of the Sun is 1.99×1030 kg. (a) What is the period of Jupiter's orbit in secon
dedylja [7]

Explanation:

It is given that,

Semi major axis of the Jupiter, a=7.78\times 10^{11}\ m

Mass of the sun, M=1.99\times 10^{30}\ kg

(a) Let T is the period of Jupiter's orbit. It is given by :

T^2\propto a^3

T^2=\dfrac{4\pi^2}{GM}a^3

T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.99\times 10^{30}}\times (7.78\times 10^{11})^3

T=3.74\times 10^8\ s

(b) We know that,

1\ year=3.154\times 10^7\ s

or

1\ s=3.171\times 10^{-8}\ year

3.74\times 10^8\ s={3.171\times 10^{-8}}\times {3.74\times 10^8}

T = 11.859 earth years

Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
A spring is stretched 2.0 cm. If the same spring is stretched 8.0 cm the ratio of the second and first potential energies of the
jok3333 [9.3K]
Potential energy of spring equals K times X squared divided by 2 where X is displacement

4 times squared equals 16

choose 1st answer
 
6 0
3 years ago
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