At what angle torque is half of max
Answer:
μ = 0.189
Explanation:
The spring potential energy will convert to work of friction
Fd = ½kx²
μmgd = ½kx²
μ = kx²/2mgd
μ = 167(0.132²) / (2(2.77)(9.81)(0.284))
μ = 0.18852424...
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