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olasank [31]
3 years ago
8

San

Physics
2 answers:
Solnce55 [7]3 years ago
7 0

Answer:

40 W

Explanation:

P = Fd/t

P = (10N )(8m)/2s

P = 80/2

P = 40 W

erica [24]3 years ago
3 0

Answer: 1) 40W

Explanation:

Power formula

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An object is lifted upward at a constant speed. The gain in potential energy of the object is due to the
Ann [662]

Answer:

b

Explanation:

7 0
3 years ago
The blood pressure of human body is greater at the feet than at the brain. why?give reason​
SOVA2 [1]

Answer:

Gravity stronger closer to the core of the earth

Explanation:

The gravity applied to the feet is stronger than to the upper part of the body for example the brain because of the distance it is between the body part and the core of the earth where the gravity force is pulling towards. Even though the difference between the gravity force between the brain and the feet is minimal it is still a greater force at the feet than at the brain

6 0
3 years ago
Which of the following scenarios will cause the current to stop flowing within a circuit?
Lelechka [254]
C is correct. Only a closed circuit can carry current, opening a switch disconnects the circuit and stops current from flowing. Remember, all current flows in loops, if you can't make a loop out of it, current can't flow, and opening a switch, assuming no other paths for current exist, will completely stop the current.
8 0
3 years ago
Read 2 more answers
PLEASE HELP DUE IN MINS. Thanks
rjkz [21]

Answer:

"C" I think....

Explanation:

I am really sorry if I am wrong, but if right, I hope this helps!

4 0
3 years ago
Read 2 more answers
A textbook of mass 2.05 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose d
blsea [12.9K]

Answer:

a. 7.38 N b. 40.87 N c. 0.113 kg-m²

Explanation:

a. Let T be the tension in the cord. For the textbook, T = ma since no other force acts on it and it is an horizontal force, and m = mass = 2.05 kg and a = acceleration. We find the acceleration from s = ut + 1/2at² where u = initial speed = 0 (since it starts from rest),  s = distance moved = 1.30 m and t = time = 0.850 s.

Substituting these values into s,

1.30 m = 0 × 0.850 + 1/2a × 0.850² = 0 + 0.36125a

1.30 = 0.36125a

a = 1.30/0.36125 = 3.6 m/s²

Substituting this into T, we have

T = ma = 2.05 kg × 3.6 m/s² = 7.38 N

b.  Let T be the tension in the cord attached to the book. The book has the only vertical forces acting on it as the tension, T(acting upwards) and its weight mg (acting downwards). So the net force acting on it is

T - mg = ma

T = m(a + g)

substituting a = 3.6 m/s² and g = 9.8 m/s² and m = 3.05 kg

T = 3.05(3.6 + 9.8) = 3.05 × 13.4 = 40.87 N

c. Since the tangential acceleration of the pulley is also the acceleration of the masses, the a = rα where r = radius of pulley = 0.200 m/2 = 0.100 m and α = angular acceleration of the pulley.

α = a/r = 3.6 m/s² ÷ 0.100 m = 36 rad/s²

Now, the torque on the pulley τ = Tr = Iα where I = moment of inertia of pulley about its rotational axis and T = tension in cord attached to book and r = radius of pulley = 0.200 m/2 = 0.100 m

From the equation above, I = Tr/α

Substituting the variables we have

I = 40.87 N × 0.100 m ÷ 36 rad/s² = 0.113 kg-m²

4 0
3 years ago
Read 2 more answers
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