All categories

3 years ago

Graph y ≥ -x^2 - 1. Click on the graph until the correct graph appears.

Mathematics

1 answer:

Nitella [24]3 years ago

6 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$y\geq -x^{2}-1$

The solution of the inequality is the shaded area above the solid line of the equation of the parabola $y= -x^{2}-1$

The vertex of the parabola is the point (0,-1)

The parabola open downward (vertex is a maximum)

using a graphing tool

see the attached figure

You might be interested in

17 points if you know. Help please

vovangra [49]

Answer:

Step-by-step explanation:

Angles 153 and QRP are straight angles, and thus Angle QRP is

180 - 153, or 27 degrees.

The interior angles of the triangle must sum up to 180 degrees:

27 + (3y + 5) + (2y - 7) = 180.

combining like terms, we get:

5y - 25 = 180, or 5y = 155, or y = 31

Then Angle Q is 3(31) + 5, or 93

Angle P is 2(31) - 7, or 55, and

Angle QRP is 27 degrees (found earlier).

6 0

3 years ago

HELLO CAN SOMEONE HELP ME IM FAILING MATH NO FAKE ANSWERS PLS TY :)

mixer [17]

Answer:

Area of rectangle = 10 units²

Area of triangle = 10 units²

Area of figure = 20 units²

Step-by-step explanation:

7 0

2 years ago

Please help!! i will mark as brainliest

Viktor [21]

Step-by-step explanation:

okay

I think you should use the method of tan 30

and then find x by using pythagorean theorem

4 0

3 years ago

Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

6 0

3 years ago

If csc θ=8/7, which equation represents cotθ

TEA [102]

Sin θ = opposite leg/hypotenuse
csc θ = hypotenuse /opposite leg =8/7

cot θ = adjacent leg/opposite leg

hypotenuse =8
opposite leg =7
We need to find adjacent leg.

(Opposite leg)² +(adjacent leg)² = hypotenuse²
7² + (adjacent leg)² =8²
(adjacent leg)² = 64 - 49
(adjacent leg)² = 15

adjacent leg=+/-√15
WE need only positive root,
so adjacent leg =√15

cot θ = √15/7 or 0.5533

6 0

3 years ago