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abruzzese [7]
3 years ago
12

As an aid in working this problem, consult concept simulation 5.2. car a uses tires for which the coefficient of static friction

is 1.1 on a particular unbanked curve. the maximum speed at which the car can negotiate this curve is 20 m/s. car b uses tires for which the coefficient of static friction is 0.7 on the same curve. what is the maximum speed at which car b can negotiate the curve?
Physics
1 answer:
4vir4ik [10]3 years ago
7 0
The speed for a curve of a given radius is proportional to the square root of the coefficient of static friction. The allowed speed in the second curve is about
  (20 m/s)√(0.7/1.1) ≈ 15.95 m/s
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A particular solid is electrically charged after it is rubbed, but it is not known whether its charge is positive or negative. H
pshichka [43]

Answer:

You can determine which charge has the solid by rubbing plastic and fur, and bringing near the plastic and the solid to determine if they are repeled or attracted. If they are repeled, the solid is charged negatively and if they are attracted, the solid is charged positively.

Explanation:

In order to determine the charge of the solid (negative or positive) using a piece of plastic and fur, you have to rubb the plastic with the fur (this is charging by friction)

Negative charges are transferred from the fur to the piece of plastic, therefore the plastic is charged negatively.

Then, you have to bring near the solid and the plastic. If them are repeled, it means that the solid is charged negatively (Because similar charges are repeled)

If them are attracted, it means that the solid is charged positively (Because opposite charges are attracted)

3 0
3 years ago
_____ have played a major role in altering Earth's atmospheric composition over time.A. TsunamisB. VolcanoesC. HurricanesD. Eart
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4 0
4 years ago
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What is the Alternative Name for responding varible
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Dependent Variable=Responding Variable.
6 0
3 years ago
A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end when it
Ilia_Sergeevich [38]

Below is the attachment of the solutions.

5 0
4 years ago
A soccer ball is kicked from the ground with an initial speed v at an upward angle θ. A player a distance d away in the directio
Nady [450]

Answer:

The speed of player is given by

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

Explanation:

The time of flight for a projectile motion is given by

T=\frac{2vsin\alpha }{g}    (i)

where t is the time of flight, v is the initial speed, and α is the angle.

Now the person must also reach the impact point of ball in the same time as above.

Now the total distance D the player needs to cover is basically R horizontal range of projectile minus the distance d, range R is given by,

R=\frac{2v^{2} sin2\alpha }{g}

Now the distance the player must cover is given by

D= R-d

D= \frac{2v^{2} sin2\alpha }{g}  - d

 

D=\frac{2v^{2}sin2\alpha-gd}{g}  (ii)

Now the average speed of player is given by

V=\frac{D}{T}   (iii)

Replacing the values of D and T from eq. (i) and (ii) in eq. (iii).

V=\frac{\frac{2v^{2} sin2\alpha-gd }{g}}{\frac{2vsin\alpha }{g} }

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

3 0
3 years ago
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