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3 years ago

A force of attraction that exists between any two objects is _______. (1 point)

1 answer:

4 0

The answer is Gravity

There's always a gravity between any 2 objects in this universe. between you and your computer, between you and the floor, between your chair and your table, etc.

We just dont feel it because we live in earth which negates all of those gravities with its own.

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The term solstice translates as "Sun stop." Explain why this translation makes sense from an astronomical point of view. It make

adoni [48]

Answer:

It makes sense because on that the day the sun stops moving northward and starts moving southward

Explanation:

4 0

3 years ago

Read 2 more answers

What do we call the distance labeled from A to B and what could we do to the note played on an instrument to change that distanc

Korvikt [17]

Correct answer choice is :

A) From A to B is known as the wavelength and changing the pitch of the note will change its length.

Explanation:

The amount or quantity of period within two things, points, lines, etc. the state or fact of existing separate in space, as of one thing from another; remoteness. a linear amount of space: Seven miles is a distance too great to walk in an hour. Distance is a scalar quantity describing the interval in two points. It is just the measure of the interval.

7 0

2 years ago

Read 2 more answers

In a crash test, a truck with mass 2100 kg traveling at 22 m/s smashes head-on into a concrete wall without rebounding. The fron

slega [8]

Answer:

a) v_average = 11 m / s, b) t = 0.0627 s

, c) F = 7.37 10⁵ N

, d) F / W = 35.8

Explanation:

a) truck speed can be found with kinematics

v² = v₀² - 2 a x

The fine speed zeroes them

a = v₀² / 2x

a = 22²/2 0.69

a = 350.72 m / s²

The average speed is

v_average = (v + v₀) / 2

v_average = (22 + 0) / 2

v_average = 11 m / s

b) The average time

v = v₀ - a t

t = v₀ / a

t = 22 / 350.72

t = 0.0627 s

c) The force can be found with Newton's second law

F = m a

F = 2100 350.72

F = 7.37 10⁵ N

.d) the ratio of this force to weight

F / W = 7.37 10⁵ / (2100 9.8)

F / W = 35.8

.e) Several approaches will be made:

- the resistance of air and tires is neglected

- It is despised that the force is not constant in time

- Depreciation of materials deformation during the crash

5 0

2 years ago

A fan at a rock concert is 50.0 m from the stage, and at this point the sound intensity level is 114 dB. Sound is detected when

Marianna [84]

Answer:

A) $P=13.92\ J.s^{-1}$

B) $v=3730.9912\ m.s^{-1}$

C) $v=74.44\ mm.s^{-1}$

D) mosquitoes speed in part B is very much larger than that of part C.

Explanation:

Given:

Distance form the sound source, $s=50\ m$

sound intensity level at the given location, $\beta=114\ dB$

diameter of the eardrum membrane in humans, $d=8.4 \times 10^{-3}\ m$

We have the minimum detectable intensity to the human ears, $I_0=10^{-12}\ W.m^{-2}$

(A)

Now the intensity of the sound at the given location is related mathematically as:

$\beta=10\ log(\frac{I}{I_0} )$ ..........................................(1)

$114=10\ log\ (\frac{I}{10^{-12}} )$

$11.4=log\ I+12\ log\ 10$

$I=0.2512\ W.m^{-2}$

As we know :

$I=\frac{P}{A}$

$0.2512=\frac{P}{\pi\times \frac{8.4^2}{4} }$

$P=13.92\ J.s^{-1}$ is the energy transferred to the eardrums per second.

(B)

mass of mosquito, $m=2\times 10^{-6}\ kg$

Now the velocity of mosquito for the same kinetic energy:

$KE=\frac{1}{2} m.v^2$

$13.92=\frac{1}{2}\times 2\times 10^{-6}\times v^2$

$v=3730.9912\ m.s^{-1}$

(C)

Given:

Sound intensity, $\beta = 20\ dB$

Using eq. (1)

$20=10\ log\ (\frac{I}{10^{-12}} )$

$2=log\ I+12\ log\ 10$

$I=10^{-10}\ W.m^{-2}$

Now, power:

$P=I.A$

$P=10^{-10}\times \pi\times \frac{8.4^2}{4}$

$P=5.54\times 10^{-9}\ J.s^{-1}$

Hence:

$KE=\frac{1}{2} m.v^2$

$5.54\times 10^{-9}=0.5\times 2\times 10^{-6}\times v^2$

$v=0.07444\ m.s^{-1}$

$v=74.44\ mm.s^{-1}$

(D)

mosquitoes speed in part B is very much larger than that of part C.

7 0

3 years ago

A 7 kg object attached to a horizontal string moves with constant speed in a circle on a frictionless horizontal surface. The ki

Marizza181 [45]

Answer:

Explanation:

Given

mass of object $m=7 kg$

kinetic Energy $k=36\ J$

Tension in string $T=326\ N$

mass is moving in a horizontal circle so tension is providing the centripetal acceleration

therefore $T=\frac{mv^2}{r}----1$

where r=radius of circle

kinetic energy of particle $k=\frac{1}{2}mv^2----2$

divide 1 and 2 we get

$\frac{T}{k}=\frac{\frac{mv^2}{r}}{\frac{1}{2}mv^2}$

$\frac{T}{k}=\frac{2}{r}$

$r=\frac{2k}{T}=\frac{2\times 36}{326}$

$r=0.2208\ m$

8 0

2 years ago