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ElenaW [278]
4 years ago
10

Kevin is 3 years older than daniel. Two years ago, Kevin was 4 times as old as Daniel. Let k be Kevin’s age and let d be Daniels

age. What system of equations would represent this situation?
Mathematics
1 answer:
bezimeni [28]4 years ago
8 0

Answer:

Daniel (now) is 3 years old,  (2 years ago) is 1 year old.

Kevin (now) is 6 years old,   (2 years ago) is 4 years old.

Step-by-step explanation:

Now:

-Kevin: k = d + 3

-Daniel: d

2 years ago:

-Kevin: k - 2 = 4(d - 2)

-Daniel: d - 2

We have the equation:

(k - 2) + 2 = k

4(d - 2) + 2 =  d + 3

4d - 8 + 2 = d + 3

3d - 6 = 3

3d = 9

d = 3

k = d + 3 = 3 + 3 = 6

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Jenna earns $7.75 per hour working at the mall. If Jenna worked 24 1/5 hours last week, how much did she earn before taxes were
Katyanochek1 [597]
24 1/5 is equal to 24.2

Multiply 24.2 by 7.75

24.2* 7.75 = 187.55

So she made $187.55 before taxes
8 0
3 years ago
What is the answer to this question?
Degger [83]

Answer:

y = -\frac{19}{9}x + \frac{5}{3}

Step-by-step explanation:

Given:

19x + 9y = 15

Required:

Rewrite in slope-intercept form, y = mx + b

SOLUTION:

19x + 9y = 15

Subtract 19x from both sides

9y = -19x + 15

Divide both sides by 9

y = -19x/9 + 15/9

y = -\frac{19}{9}x + \frac{5}{3}

5 0
3 years ago
Imagine telling a friend about your favorite coffee and donut shop. Your friend asks how much it charges for a cup of coffee and
Mama L [17]

Answer:

c + 2d = $7.00

2c + 3d = $12.00

Step-by-step explanation:

Hello!

<u>Let:</u>

  • c = # of coffees
  • d = # of donuts

1 coffee and 2 donuts cost $7.00

This can be repesented by 1c + 2d = $7.00, or c + 2d = $7.00

2 coffees and 3 donuts cost $12.00

This can be represented by 2c + 3d = $12.00

<u>So, the system is :</u>

c + 2d = $7.00

2c + 3d = $12.00

8 0
3 years ago
Georges asked five of his friends how long they studied for the last math test and what grade they received. He found a linear r
Mekhanik [1.2K]
For every hour they studied their grade will go up by 9.6 points
5 0
3 years ago
Please solve the following system of equations <br> x+3y=8 <br> 2x-y=2
Anuta_ua [19.1K]

Answer:

(2,2)

Step-by-step explanation:

Given equations are

x+3y=8       eq(1)

2x-y=2        eq(2)

we'll solve the system of equation by substitution.

Adding -3y to both sides of eq(1),we get

x+3y-3y=8-3y

x+0=8-3y

x=8-3y     eq(3)

Put above value of x in eq(2),we get

2(8-3y)-y=2

16-6y-y=2

16-7y=2

Adding -16 to both sides of above equation,we get

-16+16-7y=-16+2

0-7y=-14

-7y=-14

Dividing by -7 to both sides of above equation,we get

-7y/-7=-14/-7

y=2

Putting y=2 in eq(3),we get

x=8-3(2)

x=8-6

x=2

hence, the solution for this system of equations is (2,2).

5 0
3 years ago
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