Answer:
x=6
Step-by-step explanation:
Since this is a right triangle we can use the Pythagorean theorem
a^2 + b^2 = c^2
where a and b are the legs and c is the hypotenuse
x^2 + (x+2)^2 = (2x-2)^2
FOIL (x+2)^2 = x^2 +2x+2x+4 = x^2 +4x+4
FOIL (2x-2)^2 = 4x^2 -4x -4x+4 = 4x^2 -8x+4
Replacing these in to the equation
x^2 +x^2 +4x+4 = 4x^2 -8x+4
Combine like terms
2x^2 +4x +4 = 4x^2 -8x +4
Subtract 4 from each side
2x^2 +4x +4-4 = 4x^2 -8x +4-4
2x^2 +4x = 4x^2 -8x
Subtract 2x^2 from each side
2x^2 -2x^2+4x = 4x^2-2x^2 -8x
4x = 2x^2 -8x
Subtract 4x from each side
4x-4x = 2x^2 -8x-4x
0 = 2x^2 -12x
Factor out a 2x
0 = 2x(x-6)
Using the zero product property
2x =0 x-6 =0
x =0 x-6+6 = 0+6
x = 0 c=6
Answer:
x = 11.5
Step-by-step explanation:
The answer is C:3 if you have any more questions just let me know I will be happy to help. Have a nice day.
14-4x=2y divide 2 to both sides
VVVVV
7-2x=y you will need this on the next step
-----------------------------------------------------
y+2x=7
y=7-2x
(7-2x)+2x=7 -------> 7-2x+2x=7
7=7
The answer is C.
Answer:
14 and 2/7 minutes, or 100/7 minutes
Step-by-step explanation:
To begin with, supposed the rate at which Tyler and Kiran are running are variables T and K. We can come up with the equations
30T= 4,200 and
30K= 6,300.
Where 30 is the number of minutes, multiplied by the rate at which they are running to equal the total distance ran. We can isolate the variables by dividing both sides of both equations by 30, resulting in <u>Tyler's</u> speed of 140 meters per minute and <u>Kiran's</u> speed of 210 meters per minute.
We can then plug these values into a final equation where x is the amount of time taken for Kiran to run 1 km more than Tyler
We end up with this: 210x= 140x+1000
Solve first by subtracting 140x from 210x to get 70x, and then divide both sides by 70. This isolates x and you get a <u>final answer of 14 2/7 minutes, or 100/7 minutes</u>
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And sorry I couldn't get this to you in the 5 minutes you needed, but I hope this at least helps you understand the concept :')
