Question

What is the reaction quotient, Q, for this system when [N2] = 2.00 M, [H2] = 2.00 M, and [NH3] = 1.00 M at 472°C?

Answer 1

Answer : The value of reaction quotient, Q is 0.0625.

Solution : Given,

Concentration of $N_2$ = 2.00 M

Concentration of $H_2$ = 2.00 M

Concentration of $NH_3$ = 1.00 M

Reaction quotient : It is defined as a concentration of a chemical species involved in the chemical reaction.

The balanced equilibrium reaction is,

$N_2+3H_2\rightleftharpoons 2NH_3$

The expression of reaction quotient for this reaction is,

$Q=\frac{[Product]^p}{[Reactant]^r}\\Q=\frac{[NH_3]^2}{[N_2]^1[H_2]^3}$

Now put all the given values in this expression, we get

$Q=\frac{(1.00)^2}{(2.00)^1(2.00)^3}=0.0625$

Therefore, the value of reaction quotient, Q is 0.0625.