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Nimfa-mama [501]
3 years ago
13

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr

omagnetic radiation is emitted in each transition? n=3 --> n=2
Chemistry
1 answer:
Alecsey [184]3 years ago
5 0

Answer:

The wavelength of the emitted photon will be approximately 655 nm, which corresponds to the visible spectrum.

Explanation:

In order to answer this question, we need to recall Bohr's formula for the energy of each of the orbitals in the hydrogen atom:

E_{n} = -\frac{m_{e}e^{4}}{2(4\pi\epsilon_{0})^2\hbar^{2}}\frac{1}{n^2} = E_{1}\frac{1}{n^{2}}, where:

[tex]m_{e}[tex] = electron mass

e = electron charge

[tex]\epsilon_{0}[tex] = vacuum permittivity

[tex]\hbar[tex] = Planck's constant over 2pi

n = quantum number

[tex]E_{1}[tex] = hydrogen's ground state = -13.6 eV

Therefore, the energy of the emitted photon is given by the difference of the energy in the 3d orbital minus the energy in the 2nd orbital:

[tex]E_{3} - E_{2} = -13.6 eV(\frac{1}{3^{2}} - \frac{1}{2^{2}})=1.89 eV[tex]

Now, knowing the energy of the photon, we can calculate its wavelength using the equation:

[tex]E = \frac{hc}{\lambda}[tex], where:

E = Photon's energy

h = Planck's constant

c = speed of light in vacuum

[tex]\lambda[tex] = wavelength

Solving for [tex]\lambda[tex] and substituting the required values:

[tex]\lambda = \frac{hc}{E} = \frac{1.239 eV\mu m}{1.89 eV}=0.655\mu m = 655 nm[tex], which correspond to the visible spectrum (The visible spectrum includes wavelengths between 400 nm and 750 nm).

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The answer is Increase
4 0
2 years ago
The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?
Romashka [77]

Answer:

<h3>The answer is 400 mL</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

So we have

V_2 =  \frac{500000 \times 200}{250000}  =  \frac{100000000}{250000}  =  \frac{10000}{25}  \\

We have the final answer as

<h3>400 mL</h3>

Hope this helps you

4 0
3 years ago
When performing dimensional analysis, we usually use conversion factors. What is a conversion factor?
lora16 [44]

Answer:

A conversion factor is a variable that transforms the dimension of one variable into the terms of another variable.

Explanation:

Let be x and y two variables with diferent dimensions (units), r is a conversion if transforms the dimension of one variable into the terms of the other variable. That is:

y = r\cdot x (1)

Where:

x - Input, [input unit]

y - Output, [output unit]

r - Conversion factor, [output unit] per [input unit]

4 0
3 years ago
At what temperature does sulfur tetrafluoride have a density of 0.230 g/L at 0.0721 atm?
Allisa [31]

Explanation:

At 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide

the given mass by the number of moles to get molar mass.

Given data:

P= 0.0721 atm

n=\frac{mass}{molar \;mass}n=

molarmass

mass

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}R=0.082057338LatmK

−1

mol

−1

T=?

Putting value in the given equation:

\frac{PV}{RT}=n

RT

PV

=n

density = \frac{2 \;atm\; X molar\; mass}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}density=

0.082057338LatmK

−1

mol

−1

XT

2atmXmolarmass

0.260 g/L = \frac{0.0721 \;atm\; X 108.07 g/mol}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}0.260g/L=

0.082057338LatmK

−1

mol

−1

XT

0.0721atmX108.07g/mol

T = 365.2158727 K= 365 K

Hence , at 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.

8 0
1 year ago
A tub of water is placed in a small room. If heat is removed from the room, which of the following will most likely occur if eno
seraphim [82]
A. The water will freeze. This is because if there's not enough heat, water will freeze. Just like in winter. There's not enough heat to keep the water from melting, so it just freezes. Hope this helps!
5 0
3 years ago
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