C=12 g/mole
H=1 g/mole
O=16 g/mole
2(12)+6(1)+16=46 g/mole C2H6O
46 g/27 g =1 mole/x mole⇒ x≈0.58
the answer is about 0.58. hope helped ;)
Answer:
The total pressure of the mixture is 1.657 atm
Explanation:
Step 1: Data given
Mol fraction of H2 = 0.35
Pressure of H2 = 0.58 atm
Partial pressure gas = total pressure gas * mol fraction gas
Step 2: Calculate the total pressure
Partial pressure H2 = total pressure * mol fraction
0.58 atm = total pressure * 0.35
Total pressure = 0.58 atm / 0.35
Total pressure = 1.657 atm
The total pressure of the mixture is 1.657 atm
Answer:
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Explanation:
Normally, in the neutralization reactions, that is how the reactions between and acid and a base are called, you assume additive volumes.
Additive volumes means that the <em>volume</em> of the final <em>solution</em> is equal to the sum of the separate volumes of the two solutions that are mixed.
It is not totally accurate, but it is a good approximation and for lack of additional data it is what is used.
Then, assuming additive volumes:
- Total volume of the solution = 100 mL + 250 mL = 350 mL.
1.422 × 10^3
hope this helps!