Let
x---------> the length of the first piece
y---------> the length of the second piece
z---------> the length of the third piece
we know that
x+y+z=72 -------> equation 1
y=x+6 -----> solve for x
x=y-6 -------> equation 2
z=6+y -------> equation 3
substitute equation 2 and equation 3 in equation 1
[y-6]+y+[6+y]=72
3y=72
y=(72/3)=24 in
<u>Find the value of x</u>
x=y-6 -------> equation 2
x=24-6=18 in
<u>Find the value of z</u>
z=6+y -------> equation 3
z=6+24=30 in
therefore
<u>the answer is</u>
the length of the first piece is 18 in
the length of the second piece 24 in
the length of the third piece is 30 in
Out of 5 cards in the bag ...
-- There are 2 even numbers . . . 2 and 4 .
-- There are 3 odd numbers . . . 1, 3, and 5 .
So EITHER time, the probability of pulling an even number is 2/5 ,
and the probability of pulling an odd number is 3/5 .
The probability of pulling an even number the first time
AND an odd number the second time is
(2/5) x (3/5) = 6/25 = <em>24%</em> .
Answer: 3.36
Step-by-step explanation: 75minutes / 28= 2.678571428571429
9/2.678571428571429=3.36 times
Answer:log48
Step-by-step explanation:
3log4+log6-log8
log4^3 + log6 - log8
log(4x4x4)+log6-log8
log64 + log6 - log8
log((64x6) ➗ 8)
log(384 ➗ 8)
log48