Answer:
A. v(t) = sin (2πft + π/2) = A cos (2πft)
Step-by-step explanation:
According to trigonometry friction, the following relationship are true;
Sin(A+B) = sinAcosB + cosAsinB
We will be using this relationship to check which option is true.
Wave equation is represented as shown;
y(t) = Asin(2πft±theta)
For positive displacement,
y(t) = Asin(2πft+theta)
If theta = π/2
y(t) = Asin(2πft+π/2)
y(t) = A[ sin 2πftcosπ/2 + cos2πft sin π/2]
Since sinπ/2 = 1 and cos (π/2) = 0
y(t) = A[ sin 2πft (0)+ cos2πft (1)]
y(t) = A[0+ cos2πft]
y(t) = Acos2πft
Hence the expression that is true is expressed as;
v(t) = Asin(2πft+π/2) = Acos2πft
The distance between them is 4.0
The equation would be 1.5-(-2.5)=d
Hope that helps?
When you expand the binomial, you isolate each of the parts.
So, (x-y)^4 would turn into...
x^4 - y^4
The powers stay the same because (outside the parenthesis) you multiply them with whatever is inside the parenthesis. In this case, would be 1. All variables and numbers without a listed power have a power of one. Multiply 4*1 to get 4.
Answer:
A.) y = 0.4x^(2) + 3.4x + 4
Step-by-step explanation:
x = -5
y = -3
Answer:
im pretty sure its A
Step-by-step explanation:
