$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)$

8 0

4 years ago

Help Help Helppppppppp Help Help Help

Eva8 [605]

Answer:

164 Cm^3

Step-by-step explanation:

Solution

≈

163.6788

6 0

3 years ago

A construction crew is placing a square window in a wall The window is 3 feet wide. The wall has a width of 11 feet In order for

Fittoniya [83]

Answer:

4 feet on each side.

Step-by-step explanation:

Given :

Width of the wall = 11 feet

Width of the window = 3 feet

Now for the window to be placed in the center of window :

$=\frac{11-3}{2}$

$=\frac{8}{2}$

= 4 feet

Therefore, in order to place the window on the center of the wall, 4 feet space must be there on each side of the window.

4 0

3 years ago