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ehidna [41]
3 years ago
15

1/3(4*3)+6 can someone please help me because idr know how to solve these types of problems

Mathematics
1 answer:
disa [49]3 years ago
4 0
Simplified: 10

(4*3)=12
1/3*12=4
4+6=10
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Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
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Answer:

Length of right-angle  triangle 'a' = 4

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<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

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<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

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Given  b = 3 and hypotenuse c = 5

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<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

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