What procedure might one use to solve percent problems using proportions ?

Mathematics

1 answer:

Alborosie2 years ago

3 0

Answer:

Proportions and percent

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Which angle has a sine of -1/2 and a cosine of -√3/2

Sergeeva-Olga [200]

$\sin x=-\dfrac{1}{2} < 0\\\\\cos x=-\dfrac{\sqrt3}{2} < 0\\\\therefore\ x\in(180^o;\ 270^o)$

$\text{We know:}\ \tan x=\dfrac{\sin x}{\cos x}\\\\\text{therefore:}\ \tan x=\dfrac{-\frac{1}{2}}{-\frac{\sqrt3}{2}}=\dfrac{1}{2}\cdot\dfrac{2}{\sqrt3}=\dfrac{1}{\sqrt3}\cdot\dfrac{\sqrt3}{\sqrt3}=\dfrac{\sqrt3}{3}$

$\tan x=\dfrac{\sqrt3}{3}\Rightarrow x=30^o+180^o\cdot k;\ k\in\mathbb{Z}$

$x\in(180^o;\ 270^o)\ therefore\ \boxed{x=30^o+180^o=210^o}$

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2 years ago

How Ro U Sovle This Problem Bc I Don't Know How?

marissa [1.9K]

You would have to transform the fractions to decimals by dividing. For the first one, if you divide 4 by 5 you get .8. To transform a decimal to percent you move the decimal place 2 times to the right or multiply by 100 (They both would give you the same thing)

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3 years ago

What is 37 divided by 6 in fraction form

kotegsom [21]

Answer:

$\frac{37}{6}$ thats the answer