Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
Ten times two is equal to twenty.
Solution: The factor form of the given polynomial is 
.
Explanation:
To find the factor form of the given polynomial fisrt find the random value of x for which the vlaue of f(x) is 0.
The value of the function f(x) is 0 for 
, therefore 
is a factor of given function.
Use synthetic method to divide the given polynomial for by . Write coefficients of polynomial in top line and -1 on left side of the line. Write first element in bottom line then multiply it by -1 and write it in second line below the element second element and the add. The division by synthetic method is given in figure 1.
The bottom line shows the coefficients of the quotient polynomial.
So 
Similarly 
is the factor of given polynomial because for x=-2 the value of parenthesis polynomial is 0.
Use synthetic method to divide the parenthesis polynomial for by . it is shown in figure 2.
So
Hence the factor form of the given polynomial is . The graph of the given function is given in figure 3.
Answer:
Step-by-step explanation:
