The graph shows a nonlinear function. This is because the line is not straight. I hope this helps :) <span />
Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
12 goes into 75 6 times with a remainder of 3. So the answer will be 6 remainder 3
The distributive property: a(b + c) = ab + ac
(-7c + 8d)0.6 = (-7c)(0.6) + (8d)(0.6) = -4.2c + 4.8d
The temperature was 5 degrees below 0