Answer:
In the parallel plate capacitor,
q = e0EA, q is the charge on the plate, E is electric field intensity, A is the area of each plate, e0 = 8.854 x 10^-12F/m.
The charge density is q/A(charge per unit area)
q/A = e0 x E, from the equation above.
Therefore, q/A = 1.40 x 10^4V/m x 8.854 x 10^-12F/m
q/A = 12.3956 x 10^-8 = 1.23956 x 10^-7C/m2
Explanation:
A parallel plate capacitor consist of two plates facing eachother with separation d in between them. One of the plate is positively charged and the other is negatively charged. There is a dielectric material in between the plates. The charges on the plate is given as: q = e0EA
