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kumpel [21]
3 years ago
15

HELP ASAP!!! How many grams of lead are in a 41.2 gram sample of lead (II) oxide? With work please :)

Chemistry
1 answer:
Afina-wow [57]3 years ago
5 0
That would be 58.6 oxide because if the 41.2 plus the oxide would be 48 plus the other particcles inside it so it equaled 58.6 oxide

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Which statement best describes how an existing theory is often affected by the development of new technology?
grigory [225]

Answer: An existing theory is modified so that it can explain both the old and new observations.

Explanation:

4 0
3 years ago
What is the balanced form of the following equation? Br 2 + S 2 O 3 2– + H 2 O → Br 1– + SO 4 2– + H +
nikitadnepr [17]

Answer:

4Br₂+ 5H₂O+ S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + 8Br⁻

Explanation:

Br₂ +  S₂O₃²⁻  + H₂O  → Br⁻ + SO₄²⁻ + H⁺

This is a redox reaction:

Br₂ changes the oxidation state from 0 to -1, so it was reduced

In the S₂O₃⁻² anion S changes the oxidation state from +2 to +6 in sulfate anion. (S₂O₃⁻², it is called thiosulfate)

We have protons in the main equation, so we assume we are in acidic medium:

Br₂ + 2e⁻ → 2Br⁻         Reduction

We balanced the bromide with 2, so the bromine has gained 2 electrons.

<u>5H₂O</u> + S₂O₃²⁻ → 2SO₄²⁻ + <u>10H⁺</u> + <em>8e</em>-  Oxidation

First of all, we add 2 to the sulfate anion in the product side, in order to balance the S.

As we have 8 O in right side, and 3 O in left side, we must add 5 O. We add 5 water in the place where the O are lower (reactant side).

Now, we have 10 H, in the reactant side, so we balance the product side with protons (10 H⁺).

Sulfur changed the oxidation state from +2 to +6, so it released 4 electrons, but, if you see thiosulfate anion you have 2 sulfurs so finally it has released 8 electrons.

Electrons are unbalanced so we multiply reduction x4, and oxidation x1.

(Br₂ + 2e⁻ → 2Br⁻) . 4 = 4Br₂ + 8e⁻ → 8Br⁻

(5H₂O + S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + <em>8e</em>-) . 1 = STAYS THE SAME.

We sum both half reactions, to cancel the elecetrons:

4Br₂ + 8e⁻ + 5H₂O + S₂O₃²⁻  → 2SO₄²⁻ + 10H⁺ + <em>8e</em>- + 8Br⁻

Finally the balanced reaction is: 4Br₂+ 5H₂O+ S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + 8Br⁻

5 0
3 years ago
What are the horizontal parts of the periodic table called
Andru [333]
The Answer is Periods .
5 0
3 years ago
Is this statement true or false? Growth is caused by cells in your body dividing and making new cells.
goblinko [34]

Answer:

true

Explanation:

4 0
3 years ago
Valeric acid, HC5H9O2 (Ka = 1.5 ✕ 10−5), is used in the manufacture of magnesium valerate, a nerve-calming agent. What is the hy
Studentka2010 [4]

Answer:

[H^+]=0.00332M

Explanation:

Hello,

In this case, considering the dissociation of valeric acid as:

HC_5H_9O_2 \rightleftharpoons C_5H_9O_2 ^-+H^+

Its corresponding law of mass action is:

Ka=\frac{[H^+][C_5H_9O_2^-]}{[HC_5H_9O_2]}

Now, by means of the change x due to dissociation, it becomes:

Ka=\frac{(x)(x)}{0.737-x}=1.5x10^{-5}

Solving for x we obtain:

x=0.00332M

Thus, since the concentration of hydronium equals x, the answer is:

[H^+]=x=0.00332M

Best regards.

7 0
3 years ago
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