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kumpel [21]
3 years ago
15

HELP ASAP!!! How many grams of lead are in a 41.2 gram sample of lead (II) oxide? With work please :)

Chemistry
1 answer:
Afina-wow [57]3 years ago
5 0
That would be 58.6 oxide because if the 41.2 plus the oxide would be 48 plus the other particcles inside it so it equaled 58.6 oxide

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Formula used :

\pi =CRT\\\\\pi=\frac{w}{M\times V}RT

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C = concentration

R = solution constant  = 0.0821 L.atm/mol.K

T = temperature  = 27^oC=273+27=300K

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Now put all the given values in the above formula, we get:

0.000980atm=\frac{10.03g}{M\times 1.05L}\times (0.0821L.atm/mole.K)\times (300K)

M=2.40\times 10^5g/mol

Therefore, the molar mass of catalase is, 2.40\times 10^5g/mol

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