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adell [148]
3 years ago
14

Consider the following equilibrium:H2CO3(aq) + H2O(l) H3O+(aq) + HCO3-1(aq).What is the correct equilibrium expression?

Chemistry
1 answer:
Vanyuwa [196]3 years ago
4 0

The equilibrium expression shows the ratio between products and reactants. This expression is equal to the concentration of the products raised to its coefficient divided by the concentration of the reactants raised to its coefficient. The correct equilibrium expression for the given reaction is:<span>

<span>H2CO3(aq) + H2O(l) = H3O+(aq) + HCO3-1(aq)

Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>

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How do we turn petroleum into energy we use?
arlik [135]

You don't "turn" it into energy; petroleum HAS stored energy (chemical energy).However, you can turn it into ANOTHER TYPE OF ENERGY; usually this is done by burning the petroleum, and using it to drive machinery.

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7 0
3 years ago
Which of these has the most covalent character? <br> NaF <br> Caf2 <br> Bef2 <br> CsF <br> SrF2
VLD [36.1K]
Bef2 is the compound that has the most covalent character. Whichever element has the greatest electronegativity has the least difference and most covalent character. 
6 0
3 years ago
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A sample of silicon rejected for use in an electronic circuit has an impurity of boron at a level of 3 parts per trillion. What
Law Incorporation [45]

Answer:

A. 3 x 10-12

Explanation:

Generally, the parts-per notation is used to represent very small concentration without any specific unit.

Parts per million is notated as 10^{-6}

Parts per billion is notated as 10^{-9}

Parts per trillion is notated as 10^{-12}

Hence, 3 parts per trillion will be written as 3 x 10^{-12}

The correct option is A.

6 0
3 years ago
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What are the products in a neutralization reaction A. Two elements B.an acid and a base C. An element and a compound D. A salt a
frez [133]

D. Salt and water

Explanation:

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5 0
2 years ago
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PLEASE HELP ME!!!
kondor19780726 [428]
<h3>Answer:</h3>

0.424 J/g °C

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Chemistry</u>

<u>Thermochemistry</u>

Specific Heat Formula: q = mcΔT

  • q is heat (in Joules)
  • m is mass (in grams)
  • c is specific heat (in J/g °C)
  • ΔT is change in temperature
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] m = 38.8 g

[Given] q = 181 J

[Given] ΔT = 36.0 °C - 25.0 °C = 11.0 °C

[Solve] c

<u>Step 2: Solve for Specific Heat</u>

  1. Substitute in variables [Specific Heat Formula]:                                             181 J = (38.8 g)c(11.0 °C)
  2. Multiply:                                                                                                             181 J = (426.8 g °C)c
  3. [Division Property of Equality] Isolate <em>c</em>:                                                         0.424086 J/g °C = c
  4. Rewrite:                                                                                                             c = 0.424086 J/g °C

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.424086 J/g °C ≈ 0.424 J/g °C

6 0
2 years ago
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