Question seems to be missing. Found it on google:
a) How long is the ski jumper airborne?
b) Where does the ski jumper land on the incline?
a) 4.15 s
We start by noticing that:
- The horizontal motion of the skier is a uniform motion, with constant velocity

and the distance covered along the horizontal direction in a time t is

- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity
and constant acceleration
(where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is

The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is
below the horizontal
This happens when:

Substituting and solving for t, we find:

b) 143.6 m
Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:


The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem:

Newtons first law states that an object will remain still or in straight line. Until acted upon some force!
When the sun's rays strike Earth's surface near the equator, the incoming solar radiation is more direct (nearly perpendicular or closer to a 90˚ angle). Therefore, the solar radiation is concentrated over a smaller surface area, causing warmer temperatures.