Answer:
41.3 m/s^2 option (e)
Explanation:
force, F = 6.81 N
mass, m = 165 g = 0.165 kg
Let a be the acceleration of the puck.
Use newtons' second law
Force = mass x acceleration
6.81 = 0.165 x a
a = 41.27 m/s^2
a = 41.3 m/s^2
Thus, the acceleration of the puck is 41.3 m/s^2.
Answer:
scrim
Explanation:
A scrim is something that can be placed between the sun and the subject to diffuse the light.
An instance of a diffuser is a softbox that is put on its front side around a strobe containing diffusion content. The sun is a form of hard light that is often diffused through a scrim. The light rays are dispersed by putting a scrim between the sun and the object, and the harsh sun's rays is gentler.
The color components that will have the lowest index of refraction will be orange.
Answer:

Explanation:
As we know that resistance of one copper wire is given as

here we know that

now we have


now we know that such 17 resistors are connected in parallel so we have


Now if a single copper wire has same resistance then its diameter is D and it is given as

now from above two equations we have


now we have
