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swat32
3 years ago
10

If a car accelerates at a uniform 4.0 m/s, how long will it take to reach a speed of 36.0 m/s,

Physics
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

9s

Explanation:

v=u+at

36=0+4t

t=36-0/4

t=9s

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Write the y-equation for a wave traveling in the negative x-direction with wavelength 50 cm, speed 4.0 m/s, and amplitude 5.0 cm
Zanzabum

Answer:

y = A sin(2\pi(\dfrac{x}{50})+ 8 t)

Explanation:

given,

wavelength, λ = 50 cm

speed, v = 4 m/s

Amplitude, A = 5 cm

general equation of the wave along x- axis

y = A sin(2\pi(\dfrac{x}{\lambda})\pm \nu t)

sign is positive when wave is traveling in negative direction

now,

\nu = \dfrac{v}{\lambda}

\nu = \dfrac{4}{0.5}

\nu = 8\ s^{-1}

inserting all the values

y = A sin(2\pi(\dfrac{x}{50})+ 8 t)

Hence, the y-equation of wave is equal to y = A sin(2\pi(\dfrac{x}{50})+ 8 t)

7 0
3 years ago
If there is 8 g of a substance before a physical change , how much will there be afterwards?
Dimas [21]
A substance undergoing a physical change will still weigh the same even after the change. This is in accordance to the law of conservation of mass which states that mass is neither created nor destroyed. so an 8 g substance remains of the same weight even after undergoing a physical change.
8 0
4 years ago
Read 2 more answers
What are the two opposing forces that keep stars between collapsing and inflating?
boyakko [2]
The answer is pressure and gravity
5 0
3 years ago
4. An object is thrown vertically upward with a speed of 25 m/s. How much time passes before it
vlada-n [284]

Answer:

<em>Option b is correct: 4.1 s</em>

Explanation:

<u>Vertical Launch</u>

An object launched thrown vertically upward where air resistance is negligible, reaches its maximum height in a time t, given by the equation:

\displaystyle t=\frac{v_o}{g}\qquad\qquad[1]

Where vo is the initial speed and g is the acceleration of gravity g=9.8 m/s^2.

Once the object reaches that point, it starts a free-fall motion, whose speed is (downward) given by:

v_f=g.t\qquad\qquad[2]

The object considered in the question is thrown with vo=25 m/s. The time taken to reach the maximum height is given by [1]:

\displaystyle t=\frac{25}{9.8}=2.551\ sec

The object starts its falling motion and at some time, it has a speed of vf=15 m/s. Let's find the time by solving [2] for t:

\displaystyle t=\frac{15}{9.8}=1.531\ sec

The total time taken by the object to go up and down is

t_t=2.551\ s+1.531\ s=4.081\ s

a. This option is incorrect because it's far away from the answer.

d. This option is incorrect because it's far away from the answer.

b. This option is correct because it's a good approximation to the calculated answer.

e. This option is incorrect because it's far away from the answer.

c. This option is incorrect because it's far away from the answer.

5 0
3 years ago
A vehicle with a mass of 2,553 kg accelerates at 10 m/s2. Find the force on the vehicle in Newtons.​
Lerok [7]

Answer:

F = 25530 N

Explanation:

F(net) = ma

F(net) = 2553 kg•(10) m/s² = 25530 N

8 0
3 years ago
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