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Sedbober [7]
3 years ago
12

Which statement is true? A dilation is not a function because a point on the pre-image could be mapped to more than one point on

the image. A dilation is not a function because the image is not congruent to the pre-image. A dilation is a function because the scale factor is always greater than 1. A dilation is a function because every point on the pre-image corresponds to exactly one point on the image.
Mathematics
2 answers:
lara31 [8.8K]3 years ago
8 0

Answer:  A dilation is a function because every point on the pre-image corresponds to exactly one point on the image.

Step-by-step explanation:

  • A dilation is a transformation that creates a figure by shrinking or enlarging the original figure by using a scale factor and center of dilation.

It produces images by multiplying all distances by the same positive scale factor.

Here, every point on the pre-image corresponds to exactly one point on the image.

Then, it is a function.

[A function is a relation in which only output exists for each input.]

lianna [129]3 years ago
6 0

Here the answer is

D) A dilation is a function because every point on the pre-image corresponds to exactly one point on the image.

Definition of Dilation

Dilation stretches or shrinks the original figure.  Each pre-image point has exactly one point on the image which multiplied or reduced the scale factor.

Thank you

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Answer:

a) P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039  

P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469  

P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211  

P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422  

P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316

b) E(X) = np = 4*0.75=3

c) Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866

d) P(X \geq 3) \geq 0.98

And the dsitribution that satisfy this is X\sim Binom(n=9,p=0.75

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=4, p=1-0.25=0.75)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039  

P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469  

P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211  

P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422  

P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316

Part b

The expected value is givn by:

E(X) = np = 4*0.75=3

Part c

For the standard deviation we have this:

Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866

Part d

For this case the sample size needs to be higher or equal to 9. Since we need a value such that:

P(X \geq 3) \geq 0.98

And the dsitribution that satisfy this is X\sim Binom(n=9,p=0.75

We can verify this using the following code:

"=1-BINOM.DIST(3,9,0.75,TRUE)" and we got 0.99 and the condition is satisfied.

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