A switch
What are the answers choices
We can find the potential using the equation
V = kQ/r
Where V is the potential, k corresponds to the Coulomb constant
k = 9. 10^9 N N. m^2/C^2 ,Q is the charge and r is the radius of the sphere (r = 2.5.10^-3 m)
Substituting in the equation we obtain
V = (9. 10^9 N N. m^2/C^2)*(40.10^-12 C)/(2.5.10^-3 m) =
V = 144 V (Potential near its surface)
The object’s velocity becomes less negative, then becomes zero, and finally becomes positive.
Here's the handy factoid I always carry around in my toolbox:
When the three dimensions of a solid object all change by a factor of ' K ' . . . .
-- the surface area of the object changes by a factor of K²
-- the volume of the object changes by a factor of K³ .
So I guess if the surface area increases by 3, that means each linear dimension increased by √3, and the volume has to increase by (√3)³ .
That's 5.196 times the dog's original volume.
(And so does his weight. The poor thing is staggering around wondering what was in that last bowl of kibble that he inhaled.)
