The course to be likely taken by a mechanical engineer in college is agriculture operations (option A).
<h3>What is engineering?</h3>
Engineering is application of mathematics and the physical sciences to the needs of humanity and the development of technology.
Mechanical engineering is a subfield of engineering concerned with designing and building machines and mechanical systems.
A mechanical engineer is an individual who specialises in the field of mechanical engineering. This means that a mechanical engineer is expected to be vast in the knowledge of designing and building machines for operations in other fields.
One of those fields that a mechanical engineer can build or design machine for is agriculture. Therefore, agriculture operations is the most likely course to be taken by a mechanical engineer in college.
Learn more about mechanical engineering at: brainly.com/question/20434227
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It would be the last one. because adding fertilizers to the soil, makes the soil rich for a plant to grow "healthy"
Wait a sec.. what is a diode? i would help if i knew what that was, sorry lol
Answer:
4.5s
Explanation:
u=30m/s
v=50m/s
s=180m
a=constant(given)
By third equation of motion, v
2
=u
2
+2as
(50)
2
=(30)
2
+2a(180)
a=
3
40
m/s
2
By first equation of motion, v=u+at
50=30+(
9
40
)t
t=
2
9
=4.5sec
<h2>
Answer:</h2>
<em><u>Velocity of throwing arrow = 43.13 m/s.</u></em>
<h2>
Explanation:</h2>
In the question,
Let us say the height from which the arrow was shot = h
Distance traveled by the arrow in horizontal = 61 m
Angle made by the arrow with the ground = 2°
So,
From the <u>equations of the motion</u>,

Now,
Also,
Finally, the angle made is 2 degrees with the horizontal.
So,
Final horizontal velocity = v.cos20°
Final vertical velocity = v.sin20°
Now,
u = v.cos20° (No acceleration in horizontal)
Also,

So,
We can say that,

<em><u>Therefore, the velocity with which the arrow was shot by the archer is 43.13 m/s.</u></em>