Answer:
The right answer is "1.369 m/s²".
Explanation:
The given values are:
Distance (s)
= 260 m
Initial speed (u)
= 26 m/s
Reaction time (t')
= 0.51 s
During reaction time, the distance travelled by locomotive will be:
⇒ 
Remained distance between locomotive and car:
⇒ 
Now,
The final velocity to avoid collection is, V = 0 m/s
From third equation of motion:
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
As per Newton's III law
Every action force that is applied on an object must be equal and opposite to reaction force applied by that object.
It can be said that when we apply any force on an object then this applied force is known as action force and at the same time that object also apply an opposite direction force on us which is known as reaction force having same magnitude.
So as per above theory
Action Force = Reaction Force (magnitude)
while both forces are always opposite in direction
<span>FIRST SECTION
You should use the formula for uniformly accelerated linear movement.
Initial speed is 0 because it starts from rest.
d=(1/2)*a*t^2+vo*t =(1/2)*(4.0 m/s^2)*(3s)^2+0*3s=(1/2)*(4.0 m/s^2)*3^2*s^2+0=2.0 m*9=18m
You can calculate the final speed with the other formula:
v=a*t+vo=(4.0 m/s^2)*(3s)+0=(4.0 m/s)*(3)=12m/s
SECOND SECTION
You should use the formula for uniform linear movement.
Velocity is a constant: it remains in 12m/s.
d=v*t=12m/s*2s=12m*2=24m
THIRD SECTION
We should use the same formulas as the first section, but with different numbers.
Initial velocity will be 12m/s, and then velocity will start to decrease until it gets to 0.
We don’t know what the time is for this section.
Acceleration is negative, because it’s slowing down.
v=a*t+vo
0=-3.0 m/s^2*t+12m/s
3.0 m/s^2*t=12m/s
t=(12m/s)/(3.0 m/s^2)=4(1/s)/(1/s^2)=4s^2/s=4s
Now let’s use that time in the other formula:
d=(1/2)*a*t^2+vo*t =(1/2)*(-3.0 m/s^2)*(4s)^2+(12m/s)*3s=(-1.5 m/s^2)*4^2*s^2+12*3m*s/s=-1.5 m*4^2+36m=-1.5*16m+36m=-24m+36m=12m
Now let’s add the 3 stages:
d=18m+24m+12m=54m
</span>
Answer:
Total resistance = 0.92Ω
Explanation:
For parallel connected resistors we have effective resistance
Here parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω.
That is
R₁ = 2Ω
R₂ = 3Ω
R₃ = 4Ω
Substituting
Total resistance = 0.92Ω
Answer:
The maximum static frictional force is 40N.
Explanation:
When an object of mass M is on a surface with a coefficient of static friction μ, there is a minimum force that you need to apply to the object in order to "break" the coefficient of static friction and be able to move the object (Called the threshold of motion, once the object is moving we have a coefficient of kinetic friction, which is smaller than the one for static friction).
This coefficient defines the maximum static friction force that we can have.
So if we apply a small force and we start to increase it, the static frictional force will be equal to our force until it reaches its maximum, and then we can move the object and now we will have frictional force.
In this case, we know that we apply a force of 40N and the object just starts to move.
Then we can assume that we are just at the point of transition between static frictional force and kinetic frictional force (the threshold of motion), thus, 40 N is the maximum of the static frictional force.
