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3 years ago

Can someone please help me on this question I'm already having a bad day and I just want to get this stupid math over with

Mathematics

1 answer:

balu736 [363]3 years ago

5 0

Answer:

Option A

Step-by-step explanation:

To check which function satisfies the graph, substitute the points. Points: $(1, 12)$ is on the graph. Substitute it on the functions given in the options.

Option A: $f(1) = 20 { (\ \frac{3}{5} )\ }^1$

$\implies 4 \times 3 = 12$

Other options do not fit this $(1,12)$ . Hence Option A is our answer.

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What is 75% of 162? Show your work and/or explain your reasoning.

zhannawk [14.2K]

Answer:

121.5

Step-by-step explanation:

75% = 75/100

Step 2 - Mutiply percenatge fraction by the entire (100%) quantity

75/100× 162 = 121.5

Final result

75 percent of 162 is 121.5

3 0

2 years ago

Read 2 more answers

PLEASE HELP WITH THIS MATHS QUESTION thank you :D

trasher [3.6K]

A)106°- angle at the centre is half of the angle at the circumference

b)74°- when a tangent meets a radius a right angle is created(90+90+106)= 286 360-286= 74°

4 0

3 years ago

You know only the given information about

katrin [286]

Since they are multiples if 12

The possibilities are

12, 12, 156

12,24,144

12,36,132

12,48,120

12,60,108

12,72,96

12,84,84

24,24,132

24,36,120

24,48,108

24,60,96

24,72,84

36,36,108

36,48,96

36,60,84

36,72,72

48,48,84

48,60,72

60,60,60

Hence the probability is 1/19 or 0.0526

6 0

3 years ago

The tourists went in the first hour with a speed of 3.5km/h to the bus station, realizing that they would arrive 1 hour late at

mestny [16]

The answer should be 4.25km

7 0

3 years ago

⦁ Determine if the equation represents a direct variation. .8x = 1.6y ⦁ Suppose y varies directly with x. Write a direction vari

Mkey [24]

Part A:

Given that

$0.8x=1.6y\Rightarrow x= \frac{1.6}{0.8} y=2y$

Thus, x = ky where k = 2.

Therefore, the given equation is a direct variation.

Part B:

If y varies directly as x, then y = kx.

Given that y = 5 when x = 2, then

$5=2k \\ \\ \Rightarrow k=\frac{5}{2} =2.5 \\ \\ \Rightarrow y=2.5x$

When x = 12, y = 2.5(12) = 30.

Part C:

If y varies directly as x, then y = kx.

Given that y = 9 when x = -6, then

$9=-6k \\ \\ \Rightarrow k=-\frac{9}{6} =-\frac{3}{2} \\ \\ \Rightarrow y=-\frac{3}{2}x$

It can be seen that the equation above satisfies all the rows of the given table, therefore, y varies with x for the data in the question and the equation for the direct variation is $y=-\frac{3}{2}x$

Part 4:

If y varies directly as x, then y = kx.

Given that y = 1 when x = -2, then

$1=-2k \\ \\ \Rightarrow k=-\frac{1}{2} \\ \\ \Rightarrow y=-\frac{1}{2}x$

It can be seen that the equation above does not satisfies the other rows of the given table, therefore, y does not vary with x for the data in the question.

8 0

3 years ago

Read 2 more answers