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3 years ago

How are predator/ prey and parasite/host relationships similar

Chemistry

1 answer:

Andrews [41]3 years ago

6 0

Because predators feed on their prey, and parasites feed on their hosts. :)

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How much of a radioactive parent isotope will remain after three half-lives have passed?

Sedaia [141]

After three half lives have passed, there would be only 12.5 percent of the original amount of a radioactive parent isotope that will remain. Half life is the time needed for a certain amount of a substance to be half its initial amount. It is a common term used in nuclear chemistry describing how fast radioactive substances undergo decay. One half life would correspond to only 50% would be left. Two half lives would be 25% only of the original value. Three half lives would be 12.5%. Four half lives would be 6.25% of the initial value. So on and so forth.

4 0

3 years ago

Which statement correctly describes a chemical reaction?

Trava [24]

The correct answer is C

6 0

3 years ago

Determine the total time that must elapse until only ¼ of an original sample of the radioisotope Rn-222 remains unchanged.

Arte-miy333 [17]

Answer:

7.6 days

Explanation:

Radon is a radioactive element and Radon-222 is it's most stable isotope. The half-life of Radon-222 has been found to be approximately 3.8 days.

Let, the initial amount of the Rn-222 = 1 = A

Final amount = $\frac{1}{4}$ = A'

We will use the following relation for calculating time elapsed in the decay

$A' = A(\frac{1}{2} )^\frac{t}{t_1_/_2} }$

Thus,

$\frac{1}{4} =1(\frac{1}{2} )^\frac{t}{3.8}$

We can write is as,

$(\frac{1}{2} )^2=(\frac{1}{2} )^\frac{t}{3.8}$

Since the base in both sides are equal, powers can also be equal and thus,

$2=\frac{t}{3.8}$

So, t = 7.6 days

5 0

3 years ago

4.4 grams of CO2 represents how many moles?

jeka57 [31]

Answer:

1) Moles of CO 2 = Given mass / Molecular mass of CO 2 = 4.4 / 44 = 0.1 mole. 2) Molecules of CO2 in 0.1 moles of CO2 = 0.1 x 6.023 x 10 23 = 6.023 x 10 22 molecules 3) 44 gram (molecular wt of CO 2) contains 2 moles atom of oxygen therefore 4.4 gram of CO2 will contain = 2 /44 *4.4 = 0.2 moles atom of Oxygen.

8 0

3 years ago

Balance each of the following examples of heterogeneous equilibria and write each reaction quotient, Qc:(b) SnO₂(s) + H₂(g) ⇄ Sn

I am Lyosha [343]

When we balance this equation

SnO₂(s) + H₂(g) ⇄ Sn(s) + H₂O(g)

We will get

SnO₂(s) + 2H₂(g) ⇄ Sn(s) + 2H₂O(g)

Solution:

Balancing this equation

SnO₂(s) + H₂(g) ⇄ Sn(s) + H₂O(g)

We have to balance the number of O

SnO₂(s) + H₂(g) ⇄ Sn(s) + 2H₂O(g)

We have to balance the number of H

SnO₂(s) + 2H₂(g) ⇄ Sn(s) + 2H₂O(g)

We will get the balanced equation

SnO₂(s) + 2H₂(g) ⇄ Sn(s) + 2H₂O(g)

The reaction quotient will be

Qc = [product] / [reactant]

Qc = [Sn(s) + H₂O(g)] / [SnO₂(s) + H₂(g)]

To learn more click the given link

brainly.com/question/17144280

#SPJ4

8 0

2 years ago