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2 years ago

Question 1: Is change in atmospheric CO₂ levels likely to impact marine life?

1 answer:

3 0

1) YES science can help to answer whether CO2 levels are likely to impact marine life . yo just check how much CO2 is present in atmosphere and how much marine animals can handle it .

2) NO science cannot help to answer this question because its a matter of opinion .

Reports say that increased level of CO2 make the ocean more acidic and put marine organism s in danger .

<h3>uses of carbon dioxide:</h3>

it is used as refrigerant.

it is used in fire extinguisher.

it is used foaming rubber and plastics.

it is used in beverages, cold drinks.

it is used in bakery foods.

it promotes the growth of plants in greenhouse.

it is used as inert gas in welding.

Due to high level of CO2, ocean acidification occurs.

<h3>Ocean acidification :</h3>

when CO2 is absorbed by the sea water, a chemical reaction occur which reduce the pH of the water, carbonate ion concentration, calcium carbonate.

it has direct impact on marine animals.

it affects the reproductive life of the marine ecosystems and also it affects their respiration.

Learn more about marine animals here :

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2. What is the molarity of a HCl solution containing 1.2 grams of hydrochloric acid in 0.025 L of solution?

alisha [4.7K]

Answer:

1.3M

Explanation:

Convert from grams to moles:

molar mass of HCl = 1.01g(molar mass of H) + 35.45g(molar mass of Cl) = 36.46g HCl

1.2g HCl (1mol HCl/36.46g HCl)

= .0329 mol HCl

Molarity = mol/L (important formula for concentration)

Plug your values in:

Molarity = .0329mol/.025L

1.317M - but you used two significant figures in the question, so:

1.3M

3 0

3 years ago

Which factors affect electronegativity?

Vitek1552 [10]

I think it’s C atomic radius and numbers of unshielded protons

7 0

3 years ago

Read 2 more answers

A sample of the chiral molecule limonene is 79% enantiopure. what percentage of each enantiomer is present? what is the percent

Degger [83]

Answer : The % of (+) limonene isomer = 79%

The % of (-) limonene isomer = 0%

The % of enantiomeric excess = 58%

Explanation : Enantiomeric excess (ee) is the measurement of purity used for chiral substances.

Given,

% of pure limonene enantiomer = The % of (+) limonene isomer = 79%

Therefore, The % of (-) limonene isomer = 0%

Formula used :

$\%(+)\text{ isomer}=\frac{ee}{2}+50\%$

Where, ee → enantiomeric excess

Now, put all the values in above formula, we get the value of enantiomeric excess (ee).

${ee}=\frac{\%(+)-50\%}{2}$

$=\frac{79\%-50\%}{2}$

= 58%

7 0

3 years ago

Read 2 more answers

begging u to answer Which is not an inter molecular force? Select one: a. Inter atomic bonds b. van der waals forces c. hydrogen

Elenna [48]

Answer:

a-Interatomic bonds

Explanation:

First of all, it is not a force. Let alone be molecular force.

6 0

3 years ago

A jeweler guarantees that a piece of jewelry is at least 95% gold, by mass. You consider buying a piece of gold jewelry that wei

ELEN [110]

The density of the sample is:
Density = mass / volume
Density = 9.85 / 0.675
Density = 14.6 g/cm³

If the sample has 95% gold, and 5% silver, its density should be:
0.95 x 19.3 + 0.05 x 10.5
Theoretical density = 18.9 g/cm³

The difference in theoretical and actual densities is very large, making it likely that the jeweler was not telling the truth.

8 0

3 years ago