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Kamila [148]
3 years ago
10

Study the topographic map.

Chemistry
2 answers:
QveST [7]3 years ago
6 0

Answer:

the option is a

Explanation:

vredina [299]3 years ago
3 0
I believe it would be A.
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A solution with a ph of 4 has _________ the concentration of h+ present compared to a solution with a ph of 5.
Marina CMI [18]
<span>A solution with a pH of 4 has ten times the concentration of H</span>⁺<span> present compared to a solution with a pH of 5.
</span>pH <span>is a numeric scale for the acidity or basicity of an aqueous solution. It is  the negative of the base 10 logarithm of the molar concentration of hydrogen ions.
</span>[H⁺] = 10∧-pH.
pH = 4 → [H⁺]₁ = 10⁻⁴ M = 0,0001 M.
pH = 5 → [H⁺]₂ = 10⁻⁵ M = 0,00001 M.
[H⁺]₁ / [H⁺]₂ = 0,0001 M / 0,00001 M.
[H⁺]₁ / [H⁺]₂ = 10.
7 0
3 years ago
What substance can be used to electrolyze water? any electrolyte that is not easily reduced or oxidized hydrochloric acid only s
Alisiya [41]
<span>any electrolyte that is not easily reduced or oxidized</span>
7 0
3 years ago
Why is it important to add coefficients and not change the subscripts when balancing a chemical equation?
Artemon [7]
Because of making the equestion to be more stable and form the best compound according to it's reactant.
5 0
4 years ago
Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of
lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

U_{2}-U_{1}=Q-W

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

dw=Pdv

The pressure is constant, so:  w=P(v_{2}-v_{1} )=0.5*100*1.5=75\frac{kJ}{kg} (There is a multiplication by 100 due to the conversion of bar to kPa)

So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):

U_{2}-U_{1}=500-(3*75)=275kJ

On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:

P_{1}V_{1}=nRT_{1}

P_{2}V_{2}=nRT_{2}\\V_{2}=2.5V_{1}\\P_{2}=P_{1}\\2.5P_{1}V_{1}=nRT_{2}  

Subtracting the first from the second:

1.5P_{1}V_{1}=nR(T_{2}-T_{1})

Isolating T_{2}:

T_{2}=T_{1}+\frac{1.5P_{1}V_{1}}{nR}

Assuming that it is water steam, n=0.1666 kmol

V_{1}=\frac{nRT_{1}}{P_{1}}=\frac{8.314*0.1666*373.15}{500} =1.034m^{3}

T_{2}=100+\frac{1.5*500*1.034}{0.1666*8.314}=659.76 ºC

7 0
3 years ago
Would the solubility for a substance increase by dissolving the solute with more water?
garik1379 [7]

Answer: Yes

Explanation:

With more water, the molecules of the substance have more water molecules to form bonds with, thus they are dissolved even faster at that same particular temperature.

For example: a mildly soluble substance like powdered milk get more dissolved in your teacup as water, the solvent is increased

8 0
3 years ago
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