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MAXImum [283]
3 years ago
6

What is the constant of preportionallity in the equation y= 2.5x?

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer:

2.5

Step-by-step explanation:

y = 2.5x \\equating \: it \: with \: y \:  = kx \: where \: k \: is \: any \:  \\ constant. \\ k = 2.5 \\

Thus, constant of proportionality = 2.5

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Help lol the question is on the picture please help!
valina [46]

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7 0
3 years ago
Someone helppp!!!!!!
Yakvenalex [24]
Mother correct answer is -3,5
8 0
3 years ago
23 + 12 ×13 ÷2 Math homework
Contact [7]

Answer:

101 is your answer

Step-by-step explanation:

Remember to follow PEMDAS & the left->right rule.  

First, multiply 12 with 13:

12 x 13 = 156

Next, divide 156 with 2

156/2 = 78

Finally, add 23

78 + 23 = 101

101 is your answer

~

5 0
3 years ago
Read 2 more answers
X2 + 5x - 36
Hunter-Best [27]
What multiplied by (x-4) would make x2+5x-36
5 0
2 years ago
Read 2 more answers
Which graph represents the solution set of the system of inequalities? {x+y<12 y≥x−4
RSB [31]

Answer: The graph in the bottom right-hand corner

(see figure 4 in the attached images below)

===========================================

Explanation:

Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.

Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.

After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.

5 0
2 years ago
Read 2 more answers
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