The source below says 35.89g of NaCl dissolve in 100 g of water at 20 °C.
<span>(35.89g / 100 mL) x (2000 mL) = 718 g
Hope this helped </span>
Pollution and people littering. Can change everything.
Answer:
percentage dissociation of trimethylacetic acid in a 0.57M aqueous solution = 0.40%
Explanation:
check attachment below for more information o the answer.
Answer:
0.1056 mole
Explanation:
As Sally knows that the charge on the metal ion is n = +2

In that compartment ![$[M^{n+}]=[m^{2+}]=8.279 \ M$](https://tex.z-dn.net/?f=%24%5BM%5E%7Bn%2B%7D%5D%3D%5Bm%5E%7B2%2B%7D%5D%3D8.279%20%5C%20M%24)
The volume of the
taken in that compartment = 6.380 mL
So, the number of moles of 
= 52.82 m mol
= 0.05280 mol

But n = 2
Therefore, moles of
= 2 x moles of 
= 2 x 0.05282
= 0.1056 mole