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3 years ago

Which of the following objects does not decompose?

Chemistry

2 answers:

Virty [35]3 years ago

8 0

A plastic water bottle

Anettt [7]3 years ago

6 0

B) Plastic Water Bottle

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Write a balanced chemical equation showing how each metal oxide reacts with HCl. SrO Na2O Li2O BaO

Agata [3.3K]

Answer:

See below

Explanation:

Each metal oxide reacts with HCl to form water and the metal chloride

$\rm SrO + 2HCl \longrightarrow SrCl_{2} + H_{2}O\\\\Na_{2}O + 2HCl \longrightarrow 2NaCl + H_{2}O\\\\Li_{2}O + 2HCl \longrightarrow 2LiCl + H_{2}O\\\\BaO + 2HCl \longrightarrow BaCl_{2} + H_{2}O$

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3 years ago

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Why must reagent bottles be closed when not in use?

Katen [24]

Answer to your question.

7 0

3 years ago

Los enlaces covalentes se presentan tanto en sólidos moleculares como en los que forman una red covalente ¿porque estas clases d

Viefleur [7K]

Answer:can u anser my question

Explanation: On page 17, author Joey Bartolomeo writes “Caleb participated in the investigation by testifying about what happened during the health seminar at his school.” As it is used in that sentence, what does "testify" mean? *

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C. to persuade someone to join a group

B. to disguise or hide from sight

A. to argue so as to make a person agree

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3 years ago

Select the statements that correctly describe a buffer. a) An acid added to the buffer solution reacts with the weak base of the

Tom [10]

Answer:

(B.) The pH of a buffer solution is determined by the ratio of the concentration of conjugate base to the concentration of strong acid.
(C.) A buffer is generally made up of a weak acid and its conjugate base. 
(D.) The pH of a buffer solution does not change significantly when any amount of a strong acid is added.

Explanation:

A buffer is solution which resists change in pH upon addition of either acids or bases.

The pH of a buffer is calculated by the ratio of the concentration of base to concentration of acid. The weak acid and conjugate base have a Ka similar to the pH desired.

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3 years ago

Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m

Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is the number of moles of solute in 1 L of solution; that is

$molarity = moles of solute ÷ liters of solution$

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

Our first step is to calculate the moles of urea in 100 grams of the solution,

using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is

60.06 g/mol ÷ 37.2 g = 0.619 mol

Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.

1.032 g/mL ÷ 100 g = 96.9 mL

This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.

0.619 mol/96.9 mL × 1000 mL= 6.39 M

Therefore, the molarity of the solution is 6.39 M.

4 0

4 years ago