4 years ago

For y = 4x + 2x2-x3, show how to find the value for y, when x = 2. show work

Mathematics

1 answer:

Serga [27]4 years ago

7 0

Y(x)=4x+2x^2-x^3, when x=2

y(2)=4(2)+2(2^2)-(2^3)

y(2)=8+2(2*2)-(2*2*2)

y(2)=8+2(4)-8

y(2)=8+8-8

y(2)=8

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